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Andre45 [30]
3 years ago
8

An isosceles triangle has an angle that measures 98°. Which other angles could be in that isosceles triangle? Choose all that ap

ply.

Mathematics
1 answer:
Tamiku [17]3 years ago
4 0

an isosceles triangle is a triangle with two twin sides, and therefore two twin angles.

if one angle is 98°, well, we can't have another 98° angle because that makes 98+98 = 196°, and the sum of all interior angles in a triangle cannot be more than 180°.

so the other remaining angles must be the twin smaller angles, namely 180 - 98 = 82, and each twin takes half of that, namely 41°.


Check the picture below.

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Solve the equation using the quadratic formula. 262 – 3b+85=-5
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Answer:

b= 352/3

or b= 117.33

Step-by-step explanation:

262-3x+85=-5

-3x+(262+85)=-5

simplify the arithmetic

-3x+347=-5

Group all constants on the right side of the equation

-3x+347=-5

Subtract  from both sides:

-3x+347-347=-5-347

Simplify the arithmetic:

-3x=-5-347

-3x=-352

isolate the x

-3x=-352

Divide both sides by -3

-3x/-3}=-352/-3}

Cancel out the negatives

3x/3}=-352/-3

Simplify the fraction

x= -352/-3

Cancel out the negatives

x=352/3

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3 years ago
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4 years ago
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mario62 [17]
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4 years ago
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3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
S_A_V [24]

Answer:

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Step-by-step explanation:

We will solve the division one by one:

\frac{16x^2+48x}{8x} = \frac{8x(2x+6)}{8x} = 2x+6\\\frac{56x^2-14x}{7x}=\frac{7x(8x+2)}{7x}=8x+2\\\frac{18x^2+15x}{3x} =\frac{3x(6x+5)}{3x} = 6x+5\\\frac{20x^2-32x}{4x}=\frac{4x(5x-8)}{4x}=5x-8

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3 years ago
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