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Andre45 [30]
3 years ago
8

An isosceles triangle has an angle that measures 98°. Which other angles could be in that isosceles triangle? Choose all that ap

ply.

Mathematics
1 answer:
Tamiku [17]3 years ago
4 0

an isosceles triangle is a triangle with two twin sides, and therefore two twin angles.

if one angle is 98°, well, we can't have another 98° angle because that makes 98+98 = 196°, and the sum of all interior angles in a triangle cannot be more than 180°.

so the other remaining angles must be the twin smaller angles, namely 180 - 98 = 82, and each twin takes half of that, namely 41°.


Check the picture below.

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The first question asks to find a change in temperature. To find this, we subtract the first temperature from the last. The final temperature here is 35.65 C, while the initial is 24.85 C. Finding the change, we end up with
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4 0
3 years ago
A customer at Marty’s Fruit Stand picks a sample of 3 oranges at random from a crate containing 60 oranges, of which 4 are rotte
pychu [463]

Answer:

340 ways

Step-by-step explanation:

Given:

Total number of oranges = 60

Number of rotten oranges = 4

Number of oranges picked = 3

Now, number of good oranges = Total number - Rotten oranges

                                                    = 60 - 4 = 56

Now, we need to pick at least two rotten oranges.

So, the possible outcomes can be as follows:

  1. 2 rotten oranges + 1 good orange = 3 oranges
  2. 3 rotten oranges + 0 good orange = 3 oranges

Now, number of ways of picking 'r' distinct objects from a total of 'n' objects is given  as:

^nCr=\frac{n!}{r!(n-r)!}

Now, picking 2 rotten oranges from a total of 4 rotten oranges is:

^4C_2=\frac{4!}{2!2!}=\frac{4\times 3\times 2}{4}=6

Similarly, picking 3 rotten oranges from a total of 4 rotten oranges is:

^4C_3 =\frac{4!}{3!\times1!}=\frac{4\times 3!}{3!}=4

Now, picking 1 good orange from a total of 56 good oranges is:

^{56}C_1=56

Picking 0 good oranges means picking no good oranges.

Therefore, the total number of ways of picking at least 2 rotten oranges is the sum of the above two possibilities and is given as:

At least 2 rotten out of 3 picked = (2 rotten and 1 good) or 3 rotten

                                                       = 6 × 56 + 4

                                                       = 336 + 4 = 340 ways

Therefore, there are 340 ways of picking at least 2 rotten oranges when 3 oranges are picked from a total of 60 oranges.

8 0
4 years ago
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