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Marat540 [252]
3 years ago
5

If segment UV is considered to be the base of parallelogram TUVW, which segment would represent the altitude of the parallelogra

m?
segment TU

segment TX

segment WT

segment WV

PLEASE HELP ...?
Mathematics
1 answer:
omeli [17]3 years ago
5 0
The best and most correct answer among the choices provided by your question is the second choice or letter B.

<span>Segment TX is the segment that would best represent the altitude of the parallelogram.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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The standard deviation of the frequency distribution is 5.54

<h3>How to determine standard deviation?</h3>

The table of values is given as:

x     f(x)

0-3 13

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8-11 10

12-15 11

16-19 0

20-23 3

Rewrite the table by calculating the class midpoints:

x     f(x)

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Start by calculating the mean using:

\bar x = \frac{\sum fx}{\sum f}

This gives

\bar x = \frac{1.5 * 13 + 5.5 * 13 + 9.5 * 10 + 13.5 * 11 + 17.5 * 0 + 21.5 * 3}{13 + 13 + 10 + 11 + 0 +3}

Evaluate

\bar x = 7.98

The standard deviation is then calculated as:

\sigma = \sqrt{\frac{\sum f(x - \bar x)^2}{\sum f }}

So, we have:

\sigma= \sqrt{\frac{13 * (1.5 - 7.98)^2 + 13  * (5.5 - 7.98)^2 + (9.5 - 7.98)^2 * 10 + (13.5 - 7.98)^2 * 11 + (17.5 - 7.98)^2 * 0 + (21.5 - 7.98)^2 * 3}{13 + 13 + 10 + 11 + 0 +3}}

Evaluate

\sigma= \sqrt{30.6496}

Solve

\sigma= 5.54

Hence, the standard deviation is 5.54

Read more about standard deviation at:

brainly.com/question/15858152

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