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ryzh [129]
2 years ago
5

Determine the measure of angle A

Mathematics
1 answer:
igor_vitrenko [27]2 years ago
6 0

Answer:

63*

Step-by-step explanation:

The first thing you need to do is find the value of x. What I did for this was trial and error. I tried a number, and if it was too big, I tried a smaller one. If you add up all of the angles, it should equal up to 180*, so I kept on doing this until I added up to 180.

The answer I got was x=8, so I plugged this into the equation for A and solved. 9x8 is 72, and 72-9 is 63.

Therefore, 63 is the correct answer.

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Standard automobile license plates in a country display 2 numbers, followed by 2 letters, followed by 3 numbers. how many differ
gavmur [86]
The Standard plate combination is 6.
7 0
3 years ago
X +5+11x=12x+Y It says find the value of y that makes each equation true for all values of
sladkih [1.3K]
X + 5 + 11x = 12x + y

Simplify: 12x + 5 = 12x + y (We are adding x and 11x on the left side)

Subtract 12x from each side makes each zero.

5 = y

So we can plug in and test. I'm picking two random numbers to plug in for x. 10, and 82

x = 10, y = 5
10 + 5 + 11(10) = 12(10) + 5
125 = 125

x = 82, y = 5
82 + 5 + 11(82) = 12(82) + 5
989 = 989

So we verified y = 5
3 0
3 years ago
Please help me please !!
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5 0
2 years ago
What is the effect on the graph of the parent function f(x)=x when f(x) is replaced with f(x-7)
Stels [109]

Answer:

I think it shifts horizontally by 7 units to the right. Not completely sure though.

Step-by-step explanation:

8 0
2 years ago
How many ways can eight letters be arranged into groups of five where order matters and the first two letters are already chosen
fenix001 [56]

Answer:

120

Step-by-step explanation:

Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.

We use the permutation formula to find the answer, but before that let's check values.

n = 8

k = 5

Now since there are two letters already chosen we have to deduct two from both the value of n and k.

n = 6

k = 3

Now we can use the permutation formula:

_{n}P_{k}=\dfrac{n!}{(n-k)!}

_{6}P_{3}=\dfrac{6!}{6-3)!}

_{6}P_{3}=\dfrac{6!}{3!}

_{6}P_{3}=\dfrac{6*5*4*3*2*1}{3*2*1}

The 3*2*1 cancels out and leaves us with:

_{6}P_{3}=6*5*4

_{6}P_{3}=120

So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.

6 0
3 years ago
Read 2 more answers
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