X + 5 + 11x = 12x + y
Simplify: 12x + 5 = 12x + y (We are adding x and 11x on the left side)
Subtract 12x from each side makes each zero.
5 = y
So we can plug in and test. I'm picking two random numbers to plug in for x. 10, and 82
x = 10, y = 5
10 + 5 + 11(10) = 12(10) + 5
125 = 125
x = 82, y = 5
82 + 5 + 11(82) = 12(82) + 5
989 = 989
So we verified y = 5
The range is: 35-60
The IQR is: 11
This value is the first 25%
IQR= interquartile range
Hope this helps ;)
Answer:
I think it shifts horizontally by 7 units to the right. Not completely sure though.
Step-by-step explanation:
Answer:
120
Step-by-step explanation:
Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.
We use the permutation formula to find the answer, but before that let's check values.
n = 8
k = 5
Now since there are two letters already chosen we have to deduct two from both the value of n and k.
n = 6
k = 3
Now we can use the permutation formula:




The 3*2*1 cancels out and leaves us with:


So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.