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3 years ago

Please help for brainliest

Mathematics

1 answer:

Ilya [14]3 years ago

8 0

Answer:

D.No solution

Step-by-step explanation:

These two function are parallel (same slope) , so they would never intersect

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Find the equation of a line that passes through (-2,4) and (1,-2)

Basile [38]

$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{-2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{(-2)}}}\implies \cfrac{-6}{1+2}\implies \cfrac{-6}{3}\implies -2$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{-2}[x-\stackrel{x_1}{(-2)}]\implies y-4=-2(x+2) \\\\\\ y-4=-2x-4\implies y = -2x$

8 0

3 years ago

17)

DanielleElmas [232]

Answer:

B) 6

Step-by-step explanation: g = x - 9, g = 15 - 9. 15 - 9 = 6.

7 0

3 years ago

Read 2 more answers

(5 4 – 2) × (–2) = ? a. 22 b. –14 c. 14 d. –22

tamaranim1 [39]

The correct answer is b. -14
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6 0

3 years ago

The statement tan theta -12/5, csc theta -13/5, and the terminal point determined by theta is in quadrant 2."

Harlamova29_29 [7]

Answer:

Answer C:

Cannot be true because $csc(\theta)$ is greater than zero in quadrant 2.

Step-by-step explanation:

When the csc of an angle is negative, since the cosecant function is defined as:

$csc(\theta)=\frac{1}{sin(\theta)}$

that means that the sin of the angle must be negative, and such cannot happen in the second quadrant. The sine function is positive in the first and second quadrant.

Therefore, the correct answer is:

Cannot be true because $csc(\theta)$ is greater than zero in quadrant 2.

6 0

3 years ago

Prove that <img src="https://tex.z-dn.net/?f=2%20%5Ctan30%20%5Cdiv%201%20%2B%20tan%20%5E%7B2%7D%2030%20%3D%20sin60" id="

iVinArrow [24]

Step-by-step explanation:

2tan 30° / 1 + tan² 30° =

2(⅓√3) /1 + (⅓√3)² =

⅔√3 / 1+ ⅓ =

⅔√3 / 4/3 =

2/4 √3 =

½√3 = sin 60° (proven)

3 0

3 years ago