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timofeeve [1]
3 years ago
12

Please help for brainliest

Mathematics
1 answer:
Ilya [14]3 years ago
8 0

Answer:

D.No solution

Step-by-step explanation:

These two function are parallel (same slope) , so they would never intersect

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What is the solution to the compound inequality in interval notation?
ohaa [14]

The given compound inequality is

2(x+3)>6 \ or \ 2x+3\leq  -7

First we solve the first inequality,

2(x+3)>6
\\
x+3 >3
\\
x>0

Now we solve the second inequality

2x+3\leq -7
\\
2x \leq  -7-3
\\
2x\leq  -10
\\
x\leq  -5

So we have

x > 0 \ or  \ x\leq  -5

So the required solution is

( - \infty,-5] \ or \ (0, \infty)

Correct option is A .

4 0
3 years ago
Alec pours the same amount of soup into three balls he used 4 cups of soup how much soup is in each bowl
Ugo [173]
For this question you would need to do 4 divided by 3.  The answer would be 1.3 cup(s) would be in each bowl.


Hope that helps!!

7 0
3 years ago
Which of the following equations have complex roots?
mestny [16]

Answer:

A

Step-by-step explanation:

Complex roots of quadratic functions occur when the <u>discriminant is negative</u>.

<u>Discriminant</u>

b^2-4ac\quad\textsf{when}\:\:ax^2+bx+c=0

Evaluate the discriminant of each of the given equations.

\textsf{A.} \quad 3x^2+2=0

\implies a=3, \quad b=0, \quad c=2

\implies b^2-4ac=0^2-4(3)(2)=-24

As -24 < 0 the equation will have complex roots.

\textsf{B.} \quad 2x^2+1=7x

\implies 2x^2-7x+1=0

\implies a=2, \quad b=-7, \quad c=1

\implies b^2-4ac= (-7)^2-4(2)(1)=41

As 41 > 0 the equation does not have complex roots.

\textsf{C.} \quad 3x^2-1=6x

\implies 3x^2-6x-1=0

\implies a=3, \quad b=-6, \quad c=-1

\implies b^2-4ac=(-6)^2-4(3)(-1)=48

As 48 > 0 the equation does not have complex roots.

\textsf{D.} \quad 2x^2-1=5x

\implies 2x^2-5x-1=0

\implies a=2, \quad b=-5, \quad c=-1

\implies b^2-4ac=(-5)^2-4(2)(-1)=33

As 33 > 0 the equation does not have complex roots.

Learn more about discriminants here:

brainly.com/question/27444516

brainly.com/question/27869538

Learn more about complex roots here:

brainly.com/question/26344541

6 0
2 years ago
PLZZ HELP ME ITD MEAN THE WORLD
SSSSS [86.1K]

Answer: 33/3

Step-by-step explanation:

I don't know the question is weird but it probably is 33/3

8 0
3 years ago
Determine the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1) by following the steps below.
GaryK [48]

Answer:

Radius length: √5

Standard Form (Equation): (x + 4)^2 + y^2 = 5

Step-by-step explanation:

First we will determine the radius;

Center: (-4, 0)

Point on Circumference: (-2, 1)

d = √(-2 - (-4))^2 + (1 - 0)^2 = √(2)^2 + (1)^2

= √4 + 1 = √5

Therefore the radius is of length √5

Now the equation of a circle is in the form ((x - h)^2 + (y - k)^2) = r^2. The center is in the form (h,k) and r is the radius. Given this our equation would be (x - (-4))^2 + (y - 0)^2 = (√5)^2, or [simplified] (x + 4)^2 + y^2 = 5.

6 0
3 years ago
Read 2 more answers
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