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Andreyy89
3 years ago
10

Vector has 4 Orange picks for every 3 green picks. If 8 of the picks are orange, how many picks are green?

Mathematics
2 answers:
Serjik [45]3 years ago
6 0

Answer:

6

Step-by-step explanation:

O=orange   G=green

OOOO  : GGG = 4:3

so if orange is 8 OOOOOO it doubled by two so the green doubles by 2  GGGG

OOOOOOOO :  GGGGGG = 8:6 the answer is 6


padilas [110]3 years ago
5 0

Answer:

6. im not sure though

Step-by-step explanation:

because if he picks 4 orange and 3 are green, then it means you multiply by 2 because 4*2=8, SO 3*2=6. again, im not sure if its right or not.

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What is the answer to this question
Soloha48 [4]

(0,2),(-2,-1),(2,5)

-3x+2y=2

+3x    +3x

2y/2=3x+2/2

y=1 1/2x+2

Plug in numbers for x then solve for y

7 0
3 years ago
In65 - lnX = 39<br> What does X=?
Hunter-Best [27]

Answer:

<h2>The answer is 7.47</h2>

Step-by-step explanation:

In this problem we are going find the natural logarithmic of the numbers involved and solve for x

ln65-Ln x= 39\\

from tables

<h3> ln 65= 4.17</h3>

4.17-ln x= 39\4.17-39= lnx\\-34.83=lnx\\

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3 0
2 years ago
Which of the following is the result of the equation below after completing the square and factoring?
Tems11 [23]

Answer:

D)  (x +  \frac{5}{2})^{2}   =  \frac{9}{4}

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation

             <em>   x² + 5 x + 8 = 4</em>

    ⇒        x^{2} + 2 X \frac{5}{2} x + (\frac{5}{2} )^{2} -  (\frac{5}{2} )^{2}+ 8 = 4

<u><em>Step(ii):</em></u>-

    By using (a + b)² = a² + 2 a b + b²

  ⇒        (x +  \frac{5}{2})^{2}   -  (\frac{5}{2} )^{2}+ 8 = 4

  ⇒        (x +  \frac{5}{2})^{2}   = 4 + (\frac{5}{2} )^{2} -8

⇒           (x +  \frac{5}{2})^{2}   =  (\frac{25}{4} ) -4

⇒           (x +  \frac{5}{2})^{2}   =  (\frac{25-16}{4} )

⇒           (x +  \frac{5}{2})^{2}   =  \frac{9}{4}

<u><em>Final answer:-</em></u>

(x +  \frac{5}{2})^{2}   =  \frac{9}{4}

 

7 0
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20 POINTS!!! FIRST QUESTION TO GET IT CORRECT GETS BRAINLIEST!!
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Answer:

1320

Step-by-step explanation:

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8 0
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