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4 years ago

Which of the following algebraic expressions does not represent the word phrase, "a number times five"?

Mathematics

1 answer:

nexus9112 [7]4 years ago

4 0

$the \ answer \ is \ variant \ B \ because \ it \ can \ be \ written like: \\ \\ k5=10k+5$

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Nitrates are groundwater contaminants derived from fertilizer, septic tank seepage and other sewage. Nitrate poisoning is partic

o-na [289]

Answer:

a) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401$

And rounded up we have that n=2401

b) $n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22$

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

Part a

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.02$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have prior information about the population proportion we can use ase estimator $\hat p =0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401$

And rounded up we have that n=2401

Part b

For thi case the estimator for p is $\hat p =0.07$

$n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22$

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

4 0

3 years ago

Greatest common factor for 8x and 40

CaHeK987 [17]

The GCF of 8x and 40 is 8

40 | 2
20 | 2
10 | 2
5 | 5
1

8 | 2
4 | 2
2 | 2
1

40 = 2³ * 5
8 = 2³

We take only common factors with lowest exponent.

So 2³ = 8

4 0

3 years ago

Find the values of x for the following equations..<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B4x-98%3D0" id="TexFormula1"

Travka [436]

Hello !

Look at the picture

7 0

2 years ago

Identify the restrictions on the domain of f(x) = x+2/x-3<br> x≠-2<br> x≠2<br> x≠-3<br> x≠3

erma4kov [3.2K]

Answer:

x ≠ 3

Step-by-step explanation:

The denominator of ...

f(x) = (x+2)/(x -3)

is zero when x=3, so the function is not defined there. Values of x for which the function is not defined are not part of the domain.

The restriction is: x ≠ 3.

_____

Please note that parentheses are required around numerators and denominators when a rational function is written in plain text. When it is typeset:

$f(x)=\dfrac{x+2}{x-3}$

the division bar serves as a grouping symbol. In plain text, we cannot tell where numerator and denominator begin and end unless some other grouping symbol (parentheses) is used.

4 0

3 years ago

Anyone know the answer?

Finger [1]

The answer is going to be A.

4 0

3 years ago