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svetoff [14.1K]

3 years ago

15

In the complex number 4+ 2i, 4 is the (blank) part.

1 answer:

Talja [164]3 years ago

8 0

Answer:

4 is the real part

2 is the imaginary part

Step-by-step explanation:

A complex number is written in the form a+bi

where a is the real part and b is the imaginary part

4 +2i

4 is the real part

2 is the imaginary part

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Andrew has $2.00 in quarters in his pocket, including three state quarters. He takes two quarters out of his pocket. What is the

Zolol [24]

$2.00 in quarters is 8 quarters, since 1 quarter is 25 cents.
Out of those 8 quarters, only 3 are state quarters.
That means 5 are not state quarters.
So there is a 5/8 chance that the first quarter he takes out is not a state quarter.
If it is not, then there are 3 state quarters and 7 total quarters left, which means a 4/7 chance that the second quarter is not a state quarter.
To find the probability of both of these quarters not being state quarters, multiply the probabilities by each other.
4/7 • 5/8 = 20/56
Now simplify:
20/56 = 10/28 = 5/14
5/14 is in simplest form, so it is the answer.
So the answer is D. 5/14.

8 0

3 years ago

The decimal -2.97 is the solution to which subtraction problem?

Nat2105 [25]

Answer:
-6.1 - (-3.13) = -2.97

6 0

3 years ago

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A Rope 25 feet long is cut into 3 pieces. The first piece is 2x feet long, the second piece is 5x feet long, and the third piece

Korolek [52]

Answer:

'\/(-_-)\/'

Step-by-step explanation:

7 0

3 years ago

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A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th

QveST [7]

we know that

the volume of a cone is equal to

$V= \frac{1}{3} \pi r^{2}h$

in this problem

the radius is equal to

$r= \frac{112}{2}= 56ft$

1) <u>Find the height of the cone before the storm</u>

Applying the Pythagorean Theorem find the height

$h^{2} = l^{2}-r^{2}$

$l=65 ft$

$h^{2} = 65^{2}-56^{2}$

$h^{2} = 1,089$

$h=33 ft$

2) <u>Find the volume before the storm</u>

$V= \frac{1}{3}*\pi* 56^{2}*33$

$V=34,496\pi\ ft^{3}$

3) <u>Find the volume after the storm</u>

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

so

r=(56/3) ft

h=(33/3)=11 ft

$V= \frac{1}{3}*\pi* (56/3)^{2}*11$

$V= 1,277.63\pi\ ft^{3}$

<u>4) Find how this change affect the volume of the pile</u>

Divide the volume after the storm by the volume before the storm

$\frac{1,277.63 \pi }{34,496 \pi } = \frac{1}{27}$

therefore

<u>the answer part a) is</u>

The volume of the pile after the storm is $\frac{1}{27}$ times the original volume

<u>Part b)</u> Estimate the number of lane miles that were covered with salt

5) <u>Find the amount of salt that was used during the storm</u>

$=34,496 \pi - 1,277.63 \pi \\= 33.218.37 \pi \\= 104,358.59\ ft^{3}$

6) <u>Find the pounds of road salt used</u>

$104,358.59*80=8,348,687.2\ pounds$

7) <u>Find the number of lane miles that were covered with salt</u>

$8,348,687.2/350=23,853.39 \ lane\ miles$

therefore

<u>the answer part b) is</u>

the number of lane miles that were covered with salt is $23,853.39 \ lane\ miles$

<u>Part c) </u>How many lane miles can be covered with the remaining salt? Round your answer to the nearest lane mile

the remaining salt is equal to $1,277.63\pi\ ft^{3}$

$1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}$

8) <u>Find the pounds of road salt </u>

$4,013.79*80=321,103.20\ pounds$

9) <u>Find the number of lane miles </u>

$321,103.20/350=917.44 \ lane\ miles$

therefore

<u>the answer part c) is</u>

the number of lane miles is $917 \ lane\ miles$

7 0

4 years ago

What is the integer for -22 + (-16) =

natka813 [3]

Answer:

-38

Step-by-step explanation:

4 0

3 years ago

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