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aleksandrvk [35]
3 years ago
15

A chef prepares 1 1/2 gallons of soup in big bowl

Mathematics
2 answers:
vesna_86 [32]3 years ago
6 0
Convert gal to cup
16 cups = 1 gallon
or 16 cuos per gallon
or 16 cups/gallon

1.5 gallons × 16 cups/gallon = 24 cups
(gallons cancel out)


OverLord2011 [107]3 years ago
5 0

Answer:

One cup is 8oz. So 0 servings.

If you entered the question wrong just reply and I will attempt to help.

Step-by-step explanation:

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Help on this question please. What is the perimeter of ABC?
mestny [16]

Answer:

Step-by-step explanation

5x2=10

3x2=6

2x2=4

the answer would be 20

8 0
3 years ago
Read 2 more answers
Write an equation of the line that passes through the point(-6,-9) with slope -5
LUCKY_DIMON [66]

Answer:

  y = -5(x +6) -9

Step-by-step explanation:

The point-slope form of the equation for a line can be written as ...

  y = m(x -h) +k

for a line with slope m through point (h, k).

You have m=-5 and (h, k) = (-6, -9). Filling in these values gives ...

  y = -5(x -(-6)) -9

Simplifying a bit, you get ...

  y = -5(x +6) -9

4 0
3 years ago
Is it true or false that the measure of A is 45°
GrogVix [38]
The answer is false
8 0
3 years ago
While driving from​ Chicago, Brent had a visibility problem due to the fog. After 1 1/2
liq [111]
1) Let x be the original speed that he was driving; 

x mph ---> 1.5 hours 
x+44 mph --> 2.5 hours 

1.5x + 2.5(x+44)=206 
1.5x+2.5x+110=206 
4x=206-110 
4x=96 
x=24 
Therefore, he was travelling at 24 mph in the fog. 

2) Let x be the speed of 1 snail, 
The other snail travels at the speed of x+1 cm/min 

23x+23(x+1)=391 <-- solve for x 
23x+23x+23=391 
46x=368 
x=368/46 
x=8 

Therefore one of the snail travels at 8 cm/min while the other goes at 9 cm/min 

7) Let x be one crew 
Then the other crew would be working at x+0.5 

3.2x+3.2(x0.5)=8 <-- solve for x 
3.2x+1.6x=8 
4.8x=8 
x=8/4.8 
x=1.6666 or 1.7 miles 

Therefore, one of the crew does 1.7 miles per day and the other crew does (0.5*1.7)=0.85 miles

Hope I helped :) 
5 0
3 years ago
Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg lesss strawberries in the morning tha in the afte
Tpy6a [65]

Answer:

3\frac{13}{20}=3.65 kg.

Step-by-step explanation:        

Let S be amount of strawberries picked in the afternoon.

We have been given that Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg less strawberries in the morning than in the afternoon and the strawberries picked in morning are 2\frac{1}{4} kg.

To find the amount of strawberries picked by Sheldon in the afternoon we will add 2\frac{1}{4} and 1\frac{2}{5}  :

S= 2\frac{1}{4}+1\frac{2}{5}      

Upon converting our given mixed fractions into improper fraction we will get,

S= \frac{9}{4}+\frac{7}{5}

Now let us have a common denominator.

S=\frac{9*5}{4*5}+\frac{7*4}{5*4}

S=\frac{45}{20}+\frac{28}{20}

S=\frac{45+28}{20}

S=\frac{73}{20}  

S=3\frac{13}{20}  

S=3.65

Therefore, Sheldon picked 3\frac{13}{20}=3.65 kg of strawberries in the afternoon.  

3 0
3 years ago
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