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3 years ago

What value of y satisfies the system of equations: y=-6x+2 y=x^2+11

Mathematics

1 answer:

Nataly [62]3 years ago

8 0

Answer:

The value of y that satisfies the system of equations is 20

Step-by-step explanation:

we have

$y=-6x+2$

$y=x^{2}+11$

we know that

The solution of the system of equations is the intersection point both graphs

using a graphing tool

the intersection point is (-3,20)

see the attached figure

therefore

The value of y that satisfies the system of equations is 20

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Evaluate 18-2(10+8)/6 squared and please explain how you did it

ICE Princess25 [194]

Answer: 12

Step-by-step explanation:

18−2(10+8)/6

=18−(2)(18)/6

=18−36/6

=18−6

=12

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2 years ago

I need help to find the root?

forsale [732]

I need help to find the root?

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3 years ago

Read 2 more answers

Please help me with this homework

yulyashka [42]

I disagree. The first one is false. No exponent rules apply if the bases AND the exponents are different.

The second one is true. Bases are the sane so you add exponents. You get 3 to the -5 power. Written with positive exponents it’s 1/3 to the 5.

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3 years ago

If a tank holds 5000 gallons of water, which drains from the bottom of the tank in 40 minutes, then Torricelli's Law gives the v

pochemuha

Answer:

V'(t) = $-250(1 - \frac{1}{40}t)$

If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.

Step-by-step explanation:

Given:

V = $5000(1 - \frac{1}{40}t )^2$ , where 0≤t≤40.

Here we have to find the derivative with respect to "t"

We have to use the chain rule to find the derivative.

V'(t) = $2(5000)(1 - \frac{1}{40} t)d/dt (1 - \frac{1}{40}t )$

V'(t) = $2(5000)(1 - \frac{1}{40} t)(-\frac{1}{40} )$

When we simplify the above, we get

V'(t) = $-250(1 - \frac{1}{40}t)$

If we know the time, we can plug in the value for "t" and find how much water drained for the given point of t.

4 0

3 years ago

Two years ago, Sally had 5,000 dogs in her dog shelter. Now she has 24,575 dogs. What is the

vodomira [7]

Two years ago, Sally had 5,000 dogs in her dog shelter. Now she has 24,575 dogs. The rate of change is 391.5 % increase

<em><u>Solution:</u></em>

Given that Two years ago, Sally had 5,000 dogs in her dog shelter

Now she has 24,575 dogs

To find: rate of change

A rate of change is a rate that describes how one quantity changes in relation to another quantity

<h3><u>Steps to follow:</u></h3>

First: work out the difference (increase) between the two numbers you are comparing.

Increase = New Number - Original Number.

Then: divide the increase by the original number and multiply the answer by 100.

% change = Increase ÷ Original Number x 100

$\text {rate of change }=\frac{\text { new value }-\text {original value}}{\text {original value}} \times 100$

$\begin{array}{l}{\text { rate of change }=\frac{24,575-5000}{5000} \times 100} \\\\ {\text { rate of change }=\frac{19575}{5000} \times 100=391.5}\end{array}$

Thus the rate of change is 391.5 % increase

5 0

3 years ago