What value of y satisfies the system of equations: y=-6x+2 y=x^2+11

Mathematics

1 answer:

Nataly [62]2 years ago

8 0

Answer:

The value of y that satisfies the system of equations is 20

Step-by-step explanation:

we have

$y=-6x+2$

$y=x^{2}+11$

we know that

The solution of the system of equations is the intersection point both graphs

using a graphing tool

the intersection point is (-3,20)

see the attached figure

therefore

The value of y that satisfies the system of equations is 20

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If x and y are both negative when is x-y positive

Vladimir [108]

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x = -2
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3 years ago

Ten experts rated a newly developed chocolate chip cookie on a scale of 1 to 50. Their ratings were: 34, 35, 41, 28, 26, 29, 32,

miskamm [114]

The mean deviation of the ratings is 4.12

Explanation

The ratings of the ten experts are: 34, 35, 41, 28, 26, 29, 32, 36, 38 and 40

So, the mean of all ratings $=\frac{34+35+41+28+26+29+32+36+38+40}{10}= \frac{339}{10}=33.9$

The formula for Mean deviation $= \sum \frac{|x_{i}- \mu|}{N}$ , where $x_{i}$ is the given data from $i=1$ to $i=10$ , $\mu$ is the mean of the data and $N$ is the total number of data. So.....

$|x_{1}-\mu |= |34-33.9|=0.1\\ |x_{2}-\mu|=|35-33.9|=1.1\\ |x_{3}-\mu |=|41-33.9|=7.1\\ |x_{4}-\mu |=|28-33.9|=5.9\\ |x_{5}-\mu |=|26-33.9|=7.9\\ |x_{6}-\mu |=|29-33.9|=4.9\\|x_{7}-\mu |=|32-33.9|=1.9\\ |x_{8}-\mu |=|36-33.9|=2.1\\ |x_{9}-\mu |=|38-33.9|=4.1\\ |x_{10}-\mu |=|40-33.9|=6.1$