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Marina86 [1]
3 years ago
5

5 2/5 x 9 2/10 Please help *multiplying fractions

Mathematics
1 answer:
Maurinko [17]3 years ago
6 0

Answer:

18/5 or 3 3/5

Step-by-step explanation:

Depends if you want it simplified

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-7r2 + 7r + 2 = 2<br> Find Discriminant
victus00 [196]

Answer:

r = 1 , 0

Step-by-step explanation:

-7r^{2} + 7r + 2 = 2

-7r(r-1)=2-2

-7r(r-1)=0

r-1=0

r=1

5 0
3 years ago
Read 2 more answers
In 1950, Town A had a population of 200 people and the population increased by 200 people each year. In 1950, Town B had a popul
schepotkina [342]

Answer:

Town B will eventually overtake Town A

in 1990 Town B will have a larger population

Step-by-step explanation:

To work out how big town A will be in 1990 you need to do 200 + (200x40) because you add 40 years worth of increased population onto the starting population

To work out how big town B will be in 1990 you need to use the equation 200 X 1.1^40 because to work out plus 10 percent you need to do 1.1 and do it to the power of 40 for how many years

in 1990 town a will have a population of 8200 and town B will have a population of 9051.85

4 0
3 years ago
Write the fraction of rentals that were horror movie
agasfer [191]

Answer:

1/20

Step-by-step explanation:

if you add them all up it equals 100.And 5% was horror movies. 5/100 you divide both the top and the bottom by 5 and you get 1/20... I hope that this helpful

6 0
3 years ago
15) What is the value of y?<br> (4y - 9)<br> 40<br> 5yº
love history [14]

angle1 = 4y - 9°

angle2 = 40°

angle3 = 5y°

Angle sum property

180° = angle1 + angle2 + angle3

Therefore,

180 = (4y - 9) + 40 + 5y

180 = 4y - 9 + 40 + 5y

180 = 9y + 31

180 - 31 = 9y

149 = 9y

149/9 = y

6 0
3 years ago
A college some completed some courses worth 3 credits and some courses worth 4 credits. The students earned a total of 59 credit
Law Incorporation [45]

The student completed 13 courses with 3 credit hours.

Step-by-step explanation:

Total credit hours = 59 credits hours

Total courses = 18

Let,

3 credit hours courses = x

4 credit hours courses = y

According to statement;

x+y=18     Eqn 1

3x+4y=59   Eqn 2

Multiplying Eqn 1 by 3

3(x+y=18)\\3x+3y=54\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(3x+4y)-(3x+3y)=59-54\\3x+4y-3x-3y=5\\y=5

Putting y=5 in Eqn 1

x+5=18\\x=18-5\\x=13

The student completed 13 courses with 3 credit hours.

Keywords: linear equation, elimination method

Learn more about linear equations at:

  • brainly.com/question/12764620
  • brainly.com/question/12791734

#LearnwithBrainly

3 0
3 years ago
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