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tatuchka [14]
3 years ago
5

What’s 180 divided by 12

Mathematics
2 answers:
Sophie [7]3 years ago
8 0

The answer is 15. Take 180/12. 12  can only go into 18 1 time with a remainder of 6. bring down the 0 12 goes into 60 5 times for 60.

Blizzard [7]3 years ago
6 0
180 divided by 12 is 15 .
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Solve the equation.<br><br> 3(x−9)=30
a_sh-v [17]

Answer:

x = 19

Step-by-step explanation:

3(x - 9) = 30

Divide both sides by 3 to isolate the binomial.

x - 9 = 10

Add 9 to both sides to isolate x.

x = 19

Check your answer by plugging x = 19 back into the equation.

3(x - 9) = 30

3(19 - 9) = 30

Subtract.

3(10) = 30

Multiply.

30 = 30

Your answer is correct.

Hope this helps!

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3 years ago
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julian walked a distance of 2 meters. keira walked a distance of 300 centimeters, which distance is longer?
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300 cm is longer, since 100cm=1 meter
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3 years ago
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Which expression is equivalent to 7h^2-252k^2?
gulaghasi [49]

Answer:

c

Step-by-step explanation:

252 = 7 *36

36 = 6 *6 = 6²

a² -b²  = (a + b)(a - b)

7h² - 252k² =  7(h² - 36k²)

                   = 7(h² - [6k]² )

                  = 7(h  +6k)(h - 6k)

6 0
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How do you find a circumference of a circle?
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Step-by-step explanation:

5 0
3 years ago
Suppose yoko borrows $3500 at an interest rate of 4% compounded each year Find the amount owed at the end of 1 year
olchik [2.2K]

Amount owed at the end of 1 year is 3640

<h3><u>Solution:</u></h3>

Given that yoko borrows $3500.

Rate of interest charged is 4% compounded each year

Need to determine amount owed at the end of 1 year.

In our case :

Borrowed Amount that is principal P = $3500

Rate of interest r = 4%

Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1

<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

A=p\left(1+\frac{r}{100}\right)^{n}

Where "p" is the principal

"r" is the rate of interest

"n" is the number of years

Substituting the values in above formula we get

\mathrm{A}=3500\left(1+\frac{4}{100}\right)^{1}

\begin{array}{l}{A=\frac{3500 \times 104}{100}} \\\\ {A=35 \times 104} \\\\ {A=3640}\end{array}

Hence amount owed at the end of 1 year is 3640

5 0
3 years ago
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