What’s 180 divided by 12
2 answers:
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Answer: p = 0.9337
Step-by-step explanation: from the question, we have that
total number of pen (n)= 15
number of pen that has never been used=9
number of pen that has been used = 15 - 9 =6
number of pen choosing on monday = 3
total number of pen choosing on tuesday=3
note that the total number of pen is constant (15) since he returned the pen back .
probability of picking a pen that has never been used on tuesday = 9/15 = 3/5
probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5
probability of picking a pen that has been used on tuesday = 6/15 = 2/5
probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5
on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .
we know that
probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.
to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution
p(x=r) =
n= total number of pens=15
r = number of pen chosen on tuesday = 3
p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5
q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5
by slotting in the parameters, we have that
p(x=3) =
p(x=3) = 455 *
p(x=3) = 455 * 0.064 * 0.002176
p(x=3) = 0.0633
thus probability that 3 of the pens has been used on tuesday. = 0.0633
probability of ball that none of the 3 pen has never being used on tuesday = 1 - 0.0633 = 0.9337
The chi-squared test statistic will be 3.11. The test statistic is contrasted with a predicted value based on the Chi-square distribution.
<h3>What is the chi-squared test statistic?</h3>Finding the squared difference between the actual and anticipated data values, then dividing that difference by the expected data values, constitutes the test statistic.
The formula for the chi-squared test statistic is;
Where,
is the observed value
is the expected value
The chi-square test statics is;
Hence, the chi-squared test statistic will be 3.11.
To learn more about the chi-squared test statistic refer;
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<u>Complete Question</u>
The two-way table below gives the thousands of commuters in Massachusetts in 2015 by transportation method and one-way length of commute.
Answer:
Step-by-step explanation:
From the table above
Total Number of commuters who used public transportation=329
Number of commuters who spent 60 or more minutes on public transportation=108
Therefore:
Given that a commuter used public transportation, the probability that the commuter had a commute of 60 or more minutes:
P ( 60 + minutes ∣ public transportation ) =