Pay attention in math class! in higher grade levels, this is gonna show up EVERYDAY! no joke
In these types of problems, you need to use PEMDAS also.
((4)+3)+(13(-2)-5)
(7)+(-31)
7-31
-24
<u><em>C</em></u>
Answer:
C. h=3V/a^2 is the correct answer
Step-by-step explanation:
Given:
V=1/3a^2h
It can be rewritten as
V=1/3 *( a^2) * h
Divide both sides by (1/3)*h
V / (1/3*h) = (1/3)* (a^2) * h / (1/3)*h
V÷1/3*h = a^2
V÷3/1*h=a^2
3V/h=a^2
Multiply both sides by h
3V/h*h=h*a^2
3V=h*a^2
h=3V/a^2
C. h=3V/a^2 is the correct answer
1/6. Its just flipping the 6 around. 6=6/1.
An expression that is equivalent to ![\sqrt[5]{13^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B13%5E3%7D%20%20)
is 
The answer is B. addition or multiplication
