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3 years ago

At what point do the lines y= 2x + 3 and y = 5x - 9 intersect?

Mathematics

1 answer:

QveST [7]3 years ago

4 0

Answer:

(4,11)

Step-by-step explanation:

y=2x+3

y=5x-9

the first equation is equal to the second equation so

2x+3=5x-9

put like terms together

2x-5x= -9-3

-3x= -12

divide both sides by -3

.•.x=4

now, use the value of x to find the value of y like this:

y=2x+3 (x=4)

y=2(4)+3

y=8+3

y=11

therefore, the two lines intersect at the point (4,11)

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If ABC and EDC are similar, what is the value<br> of x?<br> A

abruzzese [7]

Answer:

x = 15

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

BC/DC = EC/AC , substitute values

3x×5/32 - 5x-5/56 ( cross- multiply )

56(3x - 5) = 32(5x - 5) ← distribute and simplify both sides

168x - 280 = 160x - 160 ( subtract 160x from both sides )

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3 0

3 years ago

11 chocolate bars cost 10 dollars

inna [77]

I'm not sure what you're trying to ask, but if you're trying to find the individual cost;

Solution: Cost of 1 candy bar is $0.91

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Hope This Helps!!!

-Austint1414

3 0

3 years ago

Find the distance between the following points using the Pythagorean theorem: (-5, 4) and (8, -3)

3241004551 [841]

First, draw a diagram to visualize the situation:

As we can see, the difference between the x-coordinates of the points is the length of one leg of a right triangle, and the difference between the y-coordinates is the length of the other leg.

Then, for the given points (-5,4) and (8,-3), the distance given by the Pythagorean Theorem is:

$\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ =\sqrt{(8--5)^2+(-3-4)^2} \\ \\ =\sqrt{(13)^2+(-7)^2} \\ \\ =\sqrt{169+49} \\ \\ =\sqrt{218} \\ \\ \approx14.7648... \end{gathered}$

Therefore, the distance between the points (-5,4) and (8,-3) is: √218.