9514 1404 393
Answer:
10.73 ft/s
Step-by-step explanation:
When the runner is halfway to first base, the triangle formed by his position and the first and second bases is a right triangle with legs of 45 ft and 90 ft. The angle between the runner's direction and the line from his position to 2nd base is ...
angle = arctan(90/45) ≈ 63.43°
The "speed made good" in the direction of 2nd base is the product of the cosine of this angle and the runner's speed toward first.
speed toward 2nd = cos(63.43°)×(24 ft/s) ≈ 10.73 ft/s
The rate the runner's distance to 2nd base is decreasing is 10.73 ft/sec.
Answer:
153.94
Step-by-step explanation:
about this amount
Answer:
90
Step-by-step explanation:
First, we should find the area of the trapezoid, and then subtract the area of the removed triangle in order to find the shaded area.
Area of the trapezoid
1) Area of the rectangle in the middle.
Base Length: 10
Height Length: 10
Area: 10 x 10 = 100
2. Area of the triangles on the side
Base Length: (14 - 10)/2 = 2
Height Length: 10
Area: 2 x 10 x 1/2 = 10
There are two triangles: 10 x 2 = 20
Area of the trapazoid: 100 + 20 = 120
Area of the triangle that's been removed
Base Length: 10
Height Length: 10 - 4 = 6
Area: 10 x 6 x 1/2 = 30
Shaded area
Area of the trapezoid - Area of the triangle
120 - 30 = 90
Area of the shaded region is 90.
<h2>1. repeat </h2><h2>2. repeat </h2><h2>3. terminate </h2><h2 />
Answer:
16
Step-by-step explanation: