That is true because as you can see in the other 2 equations, they both have z on one of the sides meaning that the sides that don't have z are equal to each other

Hope this helps :)

3 0

3 years ago

A jar contains five red marbles and three green marbles. A marble is drawn at random and not

Alex787 [66]

5+3=8
Every time you draw, its minus one from denominator

1st marble red: 5/8

2nd marble green: 3/7

5 0

3 years ago

The contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces. We are interested in testing to d

NikAS [45]

Answer:

Option b. should not be rejected

Step-by-step explanation:

We are given that the contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces.

We have to test whether the variance of the population is significantly more than 0.003, i.e.;

Null Hypothesis, $H_0$ : $\sigma$ = $\sqrt{0.003}$

Alternate Hypothesis, $H_1$ : $\sigma > \sqrt{0.003}$

The test statistics used here for testing variance is;

T.S. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, s = sample standard deviation = 0.06

n = sample size = 26 cans

So, Test statistics = $\frac{(26-1)0.06^{2} }{0.003 }$ ~ $\chi^{2}__2_5$

= 30

So, at 5% level of significance chi square table gives critical value of 37.65 at 25 degree of freedom. Since our test statistics is less than the critical so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that null hypothesis should not be rejected and variance of population is 0.003.

5 0

3 years ago

Find the slope of (-10,-4) and (5,5)

ValentinkaMS [17]

Answer:

15/9... i believe :)

7 0

3 years ago

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