Triangle formula: 1/2base(height)
So 1/2(6) * 9
3*9 = 27ft^2
Parallelogram formula: length(width) or base(height)
So 18(13)= 234m^2
Triangle formula above so 1/2(20)*9
So 10*9 = 90in^2
Given:
In △ABC is a right angle triangle.
AC is 6 units longer than side BC.

To find:
The length of AC.
Solution:
Let the length of BC be x.
So, Length of AC = x+6
According to the Pythagoras theorem, in a right angle triangle

△ABC is a right angle triangle and AC is hypotenuse, so

![[\because (a+b)^2=a^2+2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a%2Bb%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%5D)
Subtract 68 from both sides.



Divide both sides by 2.

Splitting the middle term, we get




Side cannot be negative, so x=2 only.
Now,



Therefore, the length of AC is 8 units.
Answer:
D
Step-by-step explanation:
let me know if its correct
Answer:
<h3>
-58, -57, -56</h3>
Step-by-step explanation:
x - the first of consecutive integers
x+1 - the second of consecutive integers
x+2 - the third of consecutive integers
x+x+2 - sum of the first and third integers
3(x+x+2) - three times the sum of the first and third integers
3(x+x+2) = -342
÷3 ÷3
2x + 2 = -114
-2 -2
2x = -116
÷2 ÷2
x = -58
x+1 = -58 + 1 = -57
x+2 = -58 + 2 = -56