All categories

2 years ago

What is the value of the product (3 – 2i)(3 + 2i)? 5 9 + 4i 9 – 4i 13

Mathematics

2 answers:

Assoli18 [71]2 years ago

8 0

Answer:

Step-by-step explanation:

(3-2i)(3+2i)

as (a+b)(a-b) =a²-b²

3²-(2i)²

=9-(4*-1)

=9-(-4)

=9+4

=13

Hope this helps you!

goldfiish [28.3K]2 years ago

6 0

Answer:

Step-by-step explanation:

3^2=9, 2i*(-2i)=-4i^2=4

the 6i and -6i cancel leaving the positive 9 and 4

9+4=13

You might be interested in

Step 3: Solving a system of equations to make comparisons between men and women

zysi [14]

I am also not able to solve thi s question

7 0

2 years ago

Okie is a low western lowland gorilla living at the frankline park zoo near boston, ma. he loves to fingerpaint. many of his pai

Virty [35]

13500-1500= 12000/5=2400

12000-2400= 9600

$9600 most expensive painting

5 0

2 years ago

In a secondary school class, 23 pupils study Economics, 6 pupils study both Government and Economics. 48 pupils study either Gov

Step2247 [10]

Step-by-step explanation:

I don't know this because it's so confused sorry boy or girl I'm so sorry

5 0

2 years ago

Read 2 more answers

Write a two-step equation and solve.

finlep [7]

Step-by-step explanation:

1) let number=a

six times a number=6a

Condition:

6a+4=22

2) eleven times a number=11a

Condition:

11a-5=50

3) 9 times a number=9a

Condition:

9a-7=-16

Note:if you need to ask any question please let me know.

3 0

2 years ago

Number 8 please, What are the coordinates of point C below segment AC that is partitioned at point B in a ratio of 2 to 5.

jonny [76]

$\bf \left. \qquad \right.\textit{internal division of a line segment}
\\\\\\
A(5,0)\qquad C(x,y)\qquad
\qquad 2:5
\\\\\\
\cfrac{AB}{BC} = \cfrac{2}{5}\implies \cfrac{A}{C}=\cfrac{2}{5}\implies 5A=2C\implies 5(5,0)=2(x,y)\\\\
-------------------------------\\\\
{ B=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)}$

$\bf -------------------------------\\\\
B=\left(\cfrac{(5\cdot 5)+(2\cdot x)}{2+5}\quad ,\quad \cfrac{(5\cdot 0)+(2\cdot y)}{2+5}\right)=\boxed{(8,0)}
\\\\\\
B=\left( \cfrac{25+2x}{7}~~,~~\cfrac{0+2y}{7} \right)=(8,0)\implies 
\begin{cases}
\cfrac{25+2x}{7}=8\\\\
25+2x=56\\
2x=31\\\\
\boxed{x=\cfrac{31}{2}}\\
-------\\
\cfrac{0+2y}{7}=0\\\\
2y=0\\
\boxed{y=0}
\end{cases}$

8 0

3 years ago

Read 2 more answers