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Artyom0805 [142]
3 years ago
15

I help me ?? Ok don’t know what to do

Mathematics
1 answer:
barxatty [35]3 years ago
5 0
Put the number as 12 it’s the wrong way try to put orange on angel 12 segregate f
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Please help me I just don't understand!!!!!!!!!!!!!
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Answer:

240pi

Step-by-step explanation:

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3 years ago
BD Bisects ABC. Find the value of x in the image shown below
IRISSAK [1]

Answer:

Since BD Bisects ABC,

Hence,

Angle CBD=Angle DBA

-> 55°=x°+12°

-> x° =55°-12°

-> x° =43°

6 0
3 years ago
How to solve this problem
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Step-by-step explanation:


7 0
3 years ago
Mr. Jacobs is going to make a histogram of the test scores from the last math test he gave. He plans to first organize the data
lukranit [14]
The stem and leaf plot will look like:
6 | 1 5 8 - 3 scores
7 | 1 7 7 9 - 4 scores
8 | 2 3 4 5 7 9 - 6 scores
9 | 0 1 4 7 9 - 1 score
To total up the number of students who scored less than 90, we have 3 under 60-69, 4 under 70-79, and 6 under 80-89, so this is 3 + 4 + 6. This is the third choice.
8 0
3 years ago
The minimum/maximum value of the function y = a(x − 2)(x − 1) occurs at x = d, what is the value of d?
daser333 [38]

Answer:

d=\frac{3}{2}=1.5

Step-by-step explanation:

We have the function:

y=a(x-2)(x-1)

And we want to find x=d for which the minimum/maximum value will occur.

Notice that our function is a quadratic in factored form.

Remember that the minimum/maximum value always occurs at the vertex point.

And remember that the x-coordinate of the vertex is the axis of symmetry.

Since a quadratic is always symmetrical on both sides of its axis of symmetry, a quadratic’s axis of symmetry is the average of the two roots/zeros of the quadratic.

Therefore, the value x=d such that it produces the minimum/maximum value is the average of the two roots.

Our factors are <em>(x-2) </em>and <em>(x-1)</em>.

Therefore, our roots/zeros are <em>x=1, 2</em>.

So, the average of them are:

d=\frac{1+2}{2}=3/2=1.5

Therefore, regardless of the value of <em>a</em>, the minimum/maximum value will occur at <em>x=d=1.5</em>.

Alternative Method:

Of course, we can also expand to confirm our answer. So:

y=a(x^2-2x-x+2)\\y=a(x^2-3x+2)\\y=ax^2-3ax+2a

The x-coordinate of the vertex is still going to be the place where the minimum/maximum is going to occur.

And the formula for the vertex is:

x=-\frac{b}{2a}

So, we will substitute <em>-3a</em> for <em>b</em> and <em>a</em> for <em>a</em>. This yields:

x=-\frac{-3a}{2a}=\frac{3}{2}=1.5

Confirming our answer.

4 0
2 years ago
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