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2 answers:
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Answer:
a.(10,23)
b.(7,30)
e.(20,20)
Step-by-step explanation:
We are given that
x=Width of garden
y=Length of garden
According to question
Perimeter of rectangle=
Where x=Width of rectangle
y=Length of rectangle
Fencing used =
First we change inequality into equality
...(1)
...(2)
...(3)
Substitute x=0 in equation (3)
Substitute y=0 in equation (3)
Substitute x=0 and y=0 in equation (3)
It is true. Therefore, the shaded region below the line.
These are false equation .Therefore, the shaded region above the line.
Substitute x=5 in equation (3)
Substitute y=20 in equation (3)
Intersection point of equation (1) and (3) is (5,35) and intersect point of equation (2) and (3) is (20,20).
Now,
a.(10,23)
Substitute in
10>5 and 23>20
it satisfied all inequality.
Hence, it is a solution.
b.(7,30)
7>5
30>20
it satisfied all inequality.
Hence, it is a solution.
c.(18,25)
18>5
25>20
It does not satisfied third inequality
Hence, it is not a solution.
d.(8,35)
8>5
35>20
It does not satisfied third inequality
Hence, it is not a solution.
e.(20,20)
20>5
20=20
it satisfied all inequality.
Hence, it is a solution.
Answer:
19
Step-by-step explanation:
follow the picture above
The value of k is
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y= ...........(eq iii)
Substitute the value of y into eq i
x-(= k
x- (= k
k=
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