It took me awhile, but using the Rational Root Theorem and then synthetic division I got the first root. If you don't know the RRT you'll be in heaps of trouble doing this type of problem. I found the first root to be (x+6), then I did it again and got another root of (x+6) and the third one was (x-5). So the roots of this polynomial (and there are 3 because this is a 3rd degree polynomial) are (x+6) with a multiplicity of 2, and (x-5).
The slope-intercept form is
How you submit that in your onlie env. you have to figure out using the help of that system.
Take the general slope intercept form y = mx + b and fill in both coordinates:
19 = -5m + b
13 = 5m + b
If you add them, you get a new equation with only b:
32 = 2b, so b = 16
Next, you find m, for instance by putting b back into the 2nd formula:
13 = 5m + 16
-3 = 5m
m = -3/5
Now you have found b and m to have the slope-intercept form:
Answer:
48 (my sis did this)
correct option: 137
mark me brainleast:)
Step-by-step explanation: