The area of Tinyville if the population of Tinyville is 405 Tinys while the population density of the Tinyville is 16.2 is 25 Acres.

<h3>What is Ratio?</h3>

A ratio shows us the number of times a number contains another number.

As it is given that the population density of Tinyville is 16.2 Tinys per acre, while the population of Tinyville is 405 Tinys. Therefore, the area of the Tinyville is the ratio of the population of Tinyville to the population density of the Tinyville.

$\text{Area of Tinyville} = \dfrac{\text{Population of Tinyville}}{\text{Population Density of Tinyville}}$

$\text{Area of Tinyville} = \dfrac{405}{16.2} = 25$

Hence, the area of Tinyville if the population of Tinyville is 405 Tinys while the population density of the Tinyville is 16.2 is 25 Acres.

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If the right angle triangle LMN.L=30°, MN = 4cm and diagonal LM.Find the LM and LN.​

If the right angle triangle LMN.L=30°, MN = 4cm and diagonal LM.Find the LM and LN.