32, because they gave you 6 and 10 on the right side which equals 16, and the middle bisector is a right angle you know its the same measure on the other side
The smallest possible number that is divisible by 45 when the blanked place of the number is filled is 345285.
<h3>What is the divisible rule of 9 and 5?</h3>
The divisible rule of 9 and 5 are:
- Divisible rule of 9- When the addition of all number is divisible by 9, then that number also divisible by 9.
- Divisible rule of 5- When a number has a digit 0 or 5 in the last of it, then that number also divisible by 5.
Two digits of the 6-digit number are missing.
![X = 345 * 8*](https://tex.z-dn.net/?f=X%20%3D%20345%20%2A%208%2A)
The smallest possible number from this is divisible by 45. The factors of 45 are 9 and 5.
![45=9\times5](https://tex.z-dn.net/?f=45%3D9%5Ctimes5)
Thus, the 6-digit number which is divisible by 45, must be divisible by 9 and 5.
To be divisible with 5, the number has 0 or 5 in last. So the numbers can be,
![X = 345 * 85\\X=345 * 80](https://tex.z-dn.net/?f=X%20%3D%20345%20%2A%2085%5C%5CX%3D345%20%2A%2080)
For first number, when the blank is filled with number 2 to make sum 9 and for second the blank number should be 7. Thus, the numbers,
![X = 345 285\\X=3457 80](https://tex.z-dn.net/?f=X%20%3D%20345%20285%5C%5CX%3D3457%2080)
Thus, the smallest possible number that is divisible by 45 when the blanked place of the number is filled is 345285.
Learn more about the smallest common factor here;
brainly.com/question/16054958
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