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bekas [8.4K]
3 years ago
15

What are the terms in 25p+18(p+4)

Mathematics
2 answers:
Fantom [35]3 years ago
8 0

Answer:

25p, 18p, 72

Step-by-step explanation:

Mashcka [7]3 years ago
3 0

Answer:

\Huge \boxed{43p + 72}

Step-by-step explanation:

⇒ 25p + 18(p + 4)

Distribute 18 to the terms in the brackets.

⇒ 25p + 18(p) + 18(4)

⇒ 25p + 18p + 72

Combine like terms.

⇒ (25 + 18)p + 72

⇒ 43p + 72

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2 years ago
Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,
MrRissso [65]

Answer:

4.82\cdot 10^{-4}

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

n-1=51

Therefore, the probability of drawing a three at the 2nd draw is

p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784

Then, at the third draw, the previous 2 cards are not replaced, so there are now

n-2=50

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p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08

Therefore, the total probability of drawing an ace, a three and then a jack is:

p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}

4 0
4 years ago
I need help ASAP. The assignment is due at 11:59
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3 years ago
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Answer:

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Step-by-step explanation:

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