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3 years ago

-8(x + 1) + 3(x - 2) = -3x + 2?

1 answer:

8 0

First you need to distribute the -8
So you would get -8x-8 now distribute the 3 so it would be 3x-6
-8x-8+3x-6=-3+2 is how it should look
Now combine the -8x and 3x cause their like terms and also -8 and -6
-5x-14=-3x+2 now add -3 to both sides
-2x-14=2 and add 14 to both sides
-2x=12 all left to do is divide both by -2
X=-6

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Answer:

a=5

Step-by-step explanation:

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2 years ago

What is the divisibility rule(s) for 93?

My name is Ann [436]

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3 years ago

On Sunday Sheldon bought 3 and 1/2kg of plant food. He used 1 and 2/3kg on his strawberry plants and used 1/4kg for his tomato p

notsponge [240]

The remaining plant food is: 1 7/12 kg

Step-by-step explanation:

Given

Total Plant food = 3 1/2 kg

Plant food used on Strawberry Plants = 1 2/3 kg

Plant food used on tomato Plants = 1/4 kg

We will first calculate the total food plant used and then subtract the used plant food from the total plant food.

So,

$Total\ Plant\ Food\ used=1\frac{2}{3}+\frac{1}{4}\\=\frac{5}{3}+\frac{1}{4}\\=\frac{20+3}{12}\\=\frac{23}{12}$

Now,

$Left\ Food\ Plant=3\frac{1}{2}-\frac{23}{12}\\=\frac{7}{2}-\frac{23}{12}\\=\frac{42-23}{12}\\=\frac{19}{12}\\=1\frac{7}{12}$

The remaining plant food is: 1 7/12 kg

Keywords: Division, Fractions

Learn more about fractions at:

#LearnwithBrainly

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2 years ago

Describe a real-world situation that the graph could represent. Then describe the possible values for each variable

Alex777 [14]

Answer:

$Speed=distance/time$ i.e. relation between speed-distance-time is one such situation that can be modeled using graph

Step-by-step explanation:

There are many real world examples that can be modeled using graph. Graphs are represented on co-ordinate planes, so any real world example that can be represented by use of linear equation can be represented onto a graph.

One such example, is speed-distance-time relation. Uniform speed can be represented on a graph as shown in figure.

So, the equation for speed is represented by equation as follows:

$Speed=distance/time$

So, if we take distance on y axis and time on x axis with points as (distance,time)

(0,0) ==> $v=0/0=0$

(1,2) ==> $v=1/2=0.5$

(2,2) ==> $v=2/2=1$

the following points 0,0.5,1 will be plotted on graph. Similarly, more values can be plotted by assuming values for distance and time.

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3 years ago