Answer: ![12\sqrt[3]{3}](https://tex.z-dn.net/?f=12%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
It is important to remember that:
1) ![(\sqrt[n]{a})(\sqrt[n]{b})=\sqrt[n]{ab}](https://tex.z-dn.net/?f=%28%5Csqrt%5Bn%5D%7Ba%7D%29%28%5Csqrt%5Bn%5D%7Bb%7D%29%3D%5Csqrt%5Bn%5D%7Bab%7D)
2) ![\sqrt[n]{a^n} =a^\frac{n}{n} =a](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%20%3Da%5E%5Cfrac%7Bn%7D%7Bn%7D%20%3Da)
Knowing this, and given the radical expression
, the procedure is:
Solve the multiplication:
![(2*3)\sqrt[3]{12*2} = 6\sqrt[3]{24}](https://tex.z-dn.net/?f=%282%2A3%29%5Csqrt%5B3%5D%7B12%2A2%7D%20%3D%206%5Csqrt%5B3%5D%7B24%7D)
Descompose 24 into its prime factors:

Rewriting the radicand and simplifying, we get:
![6\sqrt[3]{2^3*3} = (6)(2)\sqrt[3]{3}= 12\sqrt[3]{3}](https://tex.z-dn.net/?f=6%5Csqrt%5B3%5D%7B2%5E3%2A3%7D%20%3D%20%286%29%282%29%5Csqrt%5B3%5D%7B3%7D%3D%2012%5Csqrt%5B3%5D%7B3%7D)