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3 years ago

12

You and three friends buy 4 movie tickets. Each person buys a $3 popcorn. The total cost is $72. Letx represent the cost of 1 mo

vie ticket Write an equation for
the total cost

1 answer:

tiny-mole [99]3 years ago

6 0

4x + 12 = 72
Mmhmm yes

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consider this equation sin(theta) = -4 square root of 29/29 if theta is an angle in quadrant IV what is the value of cos (theta)

MatroZZZ [7]

Answer:

$\cos(\theta)= \frac{\sqrt{377}}{29}$

Step-by-step explanation:

Given

$\sin(\theta) = -\frac{4}{\sqrt{29}}$ -- the correct expression

Required

$\cos(\theta)$

We know that:

$\sin^2(\theta) + \cos^2(\theta)= 1$

Make $\cos^2(\theta)$ the subject

$\cos^2(\theta)= 1 - \sin^2(\theta)$

Substitute: $\sin(\theta) = -\frac{4}{\sqrt{29}}$

$\cos^2(\theta)= 1 - (-\frac{4}{\sqrt{29}})^2$

Evaluate all squares

$\cos^2(\theta)= 1 - (\frac{16}{29})$

Take LCM

$\cos^2(\theta)= \frac{29 - 16}{29}$

$\cos^2(\theta)= \frac{13}{29}$

Take square roots of both sides

$\cos(\theta)= \±\sqrt{\frac{13}{29}}$

cosine is positive in the 4th quadrant;

So:

$\cos(\theta)= \sqrt{\frac{13}{29}}$

Split

$\cos(\theta)= \frac{\sqrt{13}}{\sqrt{29}}$

Rationalize

$\cos(\theta)= \frac{\sqrt{13}}{\sqrt{29}} * \frac{\sqrt{29}}{\sqrt{29}}$

$\cos(\theta)= \frac{\sqrt{13*29}}{29}$

$\cos(\theta)= \frac{\sqrt{377}}{29}$

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3 years ago

Cual es la rais cubica de 138537 multiplicado 9 y dividido entre 58

boyakko [2]

1) Rais cubica de 138537 = 51.7434354202

2) (51.7434354202)(9) = 465.690918782

3) 465.690918782/59 = 8.0291537721

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3 years ago

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Vilka [71]

Answer:

X = 8√2.

Step-by-step explanation:

In a 45-45-90 triangle the ratio of the sides are x:x:√2 x.

So here, x = 8 and the side X = 8√2.

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4 years ago

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murzikaleks [220]

Answer:

False

Step-by-step explanation:

Let p1 be the population proportion for the first population

and p2 be the population proportion for the second population

Then

$H_{0}$ p1 = p2

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Test statistic can be found usin the equation:

$z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

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p2 is the sample population proportion for the second population

p is the pool proportion of p1 and p2

n1 is the sample size of the first population

n2 is the sample size of the second population.

As |p1-p2| gets smaller, the value of the <em>test statistic</em> gets smaller. Thus the probability of its being extreme gets smaller. This means its p-value gets higher.

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