3 years ago

2y^2-3x^2=1 is the equation of a horizontal hyperbola

1 answer:

7 0

(3x)2(2x)31 x2 1 x cxn, (2x 2) 1 2x2 (2x 2) 1 (2x) 2 2 1x 2 2x2 2 1x 2 (2x)2 2x 2
But
 (2x) 2 2 1x 2 2x2 2 1x 2 (2x)2 2x 2 lkendsnsBut

You might be interested in

What is an equation of a the line through (-1, -4) and parallel to the line 3x+y=5

Greeley [361]

Answer: y + 4 = -3(x+1)

Step-by-step explanation:

We need to rewrite in form of y=mx+b.

3x+y=5

y = -3x + 5

The slope is -3.

In addition, the slope of two parallel line would be equal, the slope of the line would be -3.

y- y1 = m(x- x1)

y- (-4) = -3(x - -1)

y + 4 = -3(x+1)

6 0

3 years ago

Christopher is thinking of two positive integers. The sum of the integers is 27. When twice the first integer is added to half o

LenKa [72]

Answer:

Let x and y be the two positive integers the Christopher is thinking.

x is equal to 7

and y =20

8 0

3 years ago

a 400 g of a liquid of density 1.6g/cm3 is made from mixing liquids of density 1.2g/cm3 and 1.8g/cm3 find the mass of the liquid

gogolik [260]

Answer:

133.33g

Step-by-step explanation:

Let the:

Mass of 1.2g/cm³ of liquid = x

Mass of 1.8g/cm³ of liquid = y

From our Question above, our system of equations is given as:

x + y = 400........ Equation 1

x = 400 - y

1.2 × x + 1.8 × y = 1.6 × 400

1.2x + 1.8y = 640..... Equation 2

We substitute, 400 - y for x in Equation 2

1.2(400 - y) + 1.8y = 640

480 - 1.2y + 1.8y = 640

- 1.2y + 1.8y = 640 - 480

0.6y = 160

y = 160/0.6y

y = 266.67 g

Solving for x

x = 400 - y

x = 400 - 266.67g

x = 133.33g

Therefore, the mass of the liquid of density 1.2g/cm³ is 133.33g

7 0

3 years ago

PQRS is a rectangle.

Anuta_ua [19.1K]

Answer:

diagram pls

then I can answer this question

8 0

3 years ago

(U-12)3 helpppppppoooppppppp

tankabanditka [31]

Answer

Step-by-step explanation:

ill help

3 0

3 years ago