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2 years ago

2y^2-3x^2=1 is the equation of a horizontal hyperbola

1 answer:

7 0

(3x)2(2x)31 x2 1 x cxn, (2x 2) 1 2x2 (2x 2) 1 (2x) 2 2 1x 2 2x2 2 1x 2 (2x)2 2x 2
But
 (2x) 2 2 1x 2 2x2 2 1x 2 (2x)2 2x 2 lkendsnsBut

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3[-x + (2 x + 1)] = x - 1 what is x

Nataly_w [17]

The answer you are looking for is x=-2.

Solution/Explanation:

Writing out the equation

3[-x+(2x+1)]=x-1

Simplifying inside of the brackets first

Combining like terms, since -x+2x=x

3(x+1)=x-1

*You can remove the parenthesis, if preferred.

Using the Distributive Property on the left side of the equation

3x+3=x-1

Now, subtracting the "x" variable from both sides

3x+3-x=x-x-1

"x-x" cancels out to 0.

3x+3-x=-1

Combining like terms and simplifying

3x-x+3=-1

2x+3=-1

Subtracting 3 from both sides of the equation

2x+3-3=-1-3

"3-3" cancels out to zero.

2x+0=-1-3

2x=-1-3

Simplifying the right side of the equation

2x=-4

Finally, dividing both sides by 2

2x/2=-4/2

Simplifying the final part of the problem

Since 2x/2=x and -4/2=-2

x=-2

So, therefore, the final answer is x=-2.

Hope that this has helped you. Good day to you.

4 0

2 years ago

If AD/DB =AE/EC, then line segment blank is parallel to line segment blank

Marysya12 [62]

Answer:DE and BC

Step-by-step explanation:

5 0

2 years ago

This is not an incomplete question, it has come from a very reliable source, please dont delete. If 60% of the students in Mr. B

nika2105 [10]

Answer:

35 students

Step-by-step explanation:

Take the number of students in the class and multiply by 60% and see if you get an integer number

28 * .60 =16.8 not an integer

32 * .6 =19.2

35 * .6 =21 yes

39*.6 =23.4

7 0

2 years ago

Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each u

cestrela7 [59]

Answer:

The amount of nuclear fuel required is 1.24 kg.

Step-by-step explanation:

From the principle of mass energy equivalence we know that energy generated by mass 'm' in an nuclear plant is

$E=m\cdot c^2$

where

'c' is the speed of light in free space

Since the power plant operates at 1200 MW thus the total energy produced in 1 year equals

$E=1200\times 10^6\times 3600\times 24\times 365=3.8\times 10^{16}Joules$

Thus using the energy produced in the energy equivalence we get

$3.8\times 10^{16}=mass\times (3\times 10^{8})^2\\\\\therefore mass=\frac{3.8\times 10^{16}}{9\times 10^{16}}=0.422kg$

Now since the efficiency of conversion is 34% thus the fuel required equals

$mass_{required}=\frac{0.422}{0.34}=1.24kg$

8 0

2 years ago

What is the solution for the quadratic equation?

N76 [4]

B since you can rewrite it as (2x+7)(x-4)=0 and you can solve it and you get B

7 0

2 years ago