All categories

2 years ago

What is the discriminant of 6x2-8x+4=0

Mathematics

1 answer:

lapo4ka [179]2 years ago

3 0

Answer:

discriminant: 64

Step-by-step explanation:

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

b^ 2 − 4 ( a c )

Substitute in the values of a , b , and c .

( − 8 )^ 2− 4 ( 6 ⋅ 0 )

Simplify each term.

Raise − 8 to the power of 2.

64 − 4 ( 6 ⋅ 0 )

Multiply 6 by 0 .

64 − 4 ⋅ 0

Multiply − 4 by 0 .

64 + 0

Add 64 and 0 .

You might be interested in

Amanda's average grade on a set of five test was 88%. She can remember only that the first four grade were 78%, 86%, 96%, and 94

Sergeeva-Olga [200]

Answer:

I think the answer is 92%.

4 0

2 years ago

If you answer these 2 questions then u like anime and i send u some pics! :)

miv72 [106K]

Um what are u saying

5 0

2 years ago

What is solution to the system of equations? Y=5×+2 3×=-y+10

Sergio [31]

Y = 5x + 2
3x = y + 10

3x = y + 10
3x = 5x + 2 + 10
3x = 5x + 12
3x - 5x = 12
-2x = 12
x = -6

substitute x = -6 into y = 5x + 2

y = 5(-6) + 2
y = -30 + 2
y = -28

x = -6, y = -28

hope this helped, God bless!

4 0

2 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

2 years ago

Examine the table below showing the merchandising sales and answer the questions that follow.

-BARSIC- [3]

Answer:

The mean amount spent = £14.80

The modal product is hoodies.

Step-by-step explanation:

Here

25 T shirts each costing £10 were purchased

Amount spent on T shirts = 25 × 10 = £250

30 key ring of £5 were purchased

Amount spent on key ring = 30 × 5 = £150

40 Hoodies for £25 each

Amount spent on Hoodies = 40 × 25 =£1000

30 CD's for £15 each

Amount spent on CD's = 30 ×15 = £450

Total amount spent = 250 +150 + 1000 + 450 = £1850

Total items purchased = 25 + 30 + 40 + 30 = 125

Mean amount spent = $\frac{1850}{125}= 14.80$

The modal product is Hoodies as the maximum number of hoodies were purchased.

6 0

3 years ago