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puteri [66]
3 years ago
13

Write and graph an equation in point slope form of the line that passes through the given point and with the given slope (3,4) m

=6
Mathematics
1 answer:
AnnyKZ [126]3 years ago
4 0
So slope intercept form y=mx+b slope is m

m=6 so
y=6x+b
this is not the legit way but it works so
put in 3 for x and 4 for y and solve for b
4=6(3)+b
4=18+b
-14=b
b=-14

the slope intercep form is y=6x-14
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A chemist is mixing two solutions, solution A and solution B Solution A is 15% water and solution Bis 20% water. She already has
slavikrds [6]

Answer:

15 mL of the solution with 20% water will be needed.

Step-by-step explanation:

Use the inverse relationship

10 mL * (18-15)% = x mL * (20-18)%

x = 10 mL * (3/2) = 15 mL

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3 years ago
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Which graph represents the solution set for the system 2x + 5y ≤ 9 and 3x + 5y ≤ 9?
Solnce55 [7]
The answer is graph B. Have a nice day!
6 0
3 years ago
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Plz help me with this
AnnZ [28]

Answer:  \bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, B=\dfrac{6}{5}  →   P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}

Half of that period is: \dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}

Calculate the period for each of the options to find a match:

A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}

7 0
3 years ago
Help!!!! Number 4 right answer
USPshnik [31]
The answer would be 0 solutions.

Here, we see <em>|</em><em />x+6<em>|</em><em /> = 2.
Oh wow! A foreign object!
|x+6|... two lines... what is that?

That is called absolute value. Whatever is inside the two lines, must have a positive answer!

Let's pretend we have a machine that has this absolute value function activated.
What we put in, we must get a positive answer out.

Let's put in -6.

-6 ==> BEEP BEEP ==> 6

Let's try 3.

3 ==> BEEP BEEP ==>3

Whatever we put in, if it is negative or positive, what comes out is always positive.  

So, for how many values <em>x</em> is |x+6|=-2 true?

None, because the answer <em>must</em><em /> be positive! 
-2 is not positive, <em>2</em><em /> is.

8 0
3 years ago
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