As we know that the standard equation of circle is
, where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>
Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>
Now , putting values in our standard equation ;
<em>This is the required equation of </em><em>Circle</em>
Refer to the attachment as well !
Answer:
umm help with what
Step-by-step explanation:
Answer:
4 dimes
2 nickels
Step-by-step explanation:
Answer:
(x-y)(x+6)
Step-by-step explanation:
x^2+6x-xy-6y
x*(x+6)-y(x+6)
(x-y)(x+6)