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Eva8 [605]
2 years ago
11

In triangle FGH, the measure of angle F=42 and an exterior angle at vertex H has a measure of 104. what is the measure of angle

G
Mathematics
1 answer:
qaws [65]2 years ago
5 0

Answer:

Angle G = 62.

Step-by-step explanation:

The exterior angle at H is 104. Subtract 104 from 180 to get the interior angle H = 76.

Add interior angles F and H to get 118. Subtract:

180 total degrees in a triangle minus 118 for Angles F and H.

180 - 118 = 62

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erastovalidia [21]

Answer:

1. KLP + PLM = 180 degrees (straight line)

2. 3x + angle PLM = 180 degrees

3. angle PLM = 180 - 3x

4. PMN = P + PLM (Exterior angle)

5. 2x + 72 = x + 180 - 3x

6. x = 27

Step-by-step explanation:

1. Notice that angle KLP + angle PLM is a straight line, so KLP + PLM = 180 degrees (straight line)

2. angle KLP = 3x, so

3x + angle PLM = 180 degrees

3. angle PLM = 180 - 3x

4. PMN = P + PLM (Exterior angle)

5. 2x + 72 = x + 180 - 3x

6. 5 gives 4x = 108, so x = 27

6 0
3 years ago
Read 2 more answers
Hello whats is the size of the angle
Gennadij [26K]

Answer:

x = 65°

Step-by-step explanation:

The interior angle of the triangle and 140° are adjacent and supplementary, thus

interior angle = 180° - 140° = 40°

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

105° is an exterior angle of the triangle, thus

x + 40° = 105° ( subtract 40° from both sides )

x = 65°

4 0
3 years ago
Read 2 more answers
Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC . FIRST CORRECT ANSWER GETS POINTS AND BRAINLIEST!!!! T
Ad libitum [116K]

Answer:

Given : In △ABC, m∠A=60°, m∠C=45°,and AB=8 unit

Firstly, find the angles B

Sum of measures of the three angles of any triangle equal to the straight angle, and also expressed as 180 degree

∴m∠A+ m∠B+m∠C=180                      ......[1]

Substitute the values of m∠A=60° and m∠C=45° in [1]

60^{\circ}+ m\angle B+45^{\circ}=180^{\circ}

105^{\circ}+ m\angle B=180^{\circ}

Simplify:

m\angle B=75^{\circ}

Now, find the sides of BC

For this, we can use law of sines,

Law of sine rule is an equation relating the lengths of the sides of a triangle  to the sines of its angles.

\frac{\sin A}{BC} = \frac{\sin C}{AB}

Substitute the values of ∠A=60°, ∠C=45°,and AB=8 unit to find BC.

\frac{\sin 60^{\circ}}{BC} =\frac{\sin 45^{\circ}}{8}

then,

BC = 8 \cdot \frac{\sin 60^{\circ}}{\sin 45^{\circ}}

BC=8 \cdot \frac{0.866025405}{0.707106781} =9.798 unit

Similarly for  AC:

\frac{\sin B}{AC} = \frac{\sin C}{AB}

Substitute the values of ∠B=75°, ∠C=45°,and AB=8 unit to find AC.

\frac{\sin 75^{\circ}}{AC} =\frac{\sin 45^{\circ}}{8}

then,

AC = 8 \cdot \frac{\sin 75^{\circ}}{\sin 45^{\circ}}

AC=8 \cdot \frac{0.96592582628}{0.707106781} =10.9283 unit

To find the perimeter of triangle ABC;

Perimeter = Sum of the sides of a triangle

i,e

Perimeter of △ABC = AB+BC+AC = 8 +9.798+10.9283 = 28.726 unit.

To find the area(A) of triangle ABC ;

Use the formula:

A = \frac{1}{2} \times AB \times AC \times \sin A

Substitute the values in above formula to get area;

A=\frac{1}{2} \times 8 \times 10.9283 \times \sin 60^{\circ}

A = 4 \times 10.9283 \times 0.86602540378

Simplify:

Area of triangle ABC = 37.856 (approx) square unit





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