According to a survey of adults, 64 percent have money in a bank savings account. If we were to survey 50 randomly selected adul
1 answer:
Answer:
The mean number of adults who would have bank savings accounts is 32.
Step-by-step explanation:
For each adult surveyed, there are only two possible outcomes. Either they have bank savings accounts, or they do not. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
In this problem, we have that:
If we were to survey 50 randomly selected adults, find the mean number of adults who would have bank savings accounts.
This is E(X) when .
So
The mean number of adults who would have bank savings accounts is 32.
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15 students preordered the year book and 9 students paid full price.
<u>Solution: </u>
Given that
Cost of pre-ordered year book = each
Cost of full price of year book = each
Number of students in Mr. Hillman's class purchased yearbooks = 24
Total price spent by 24 students to purchase year book =
Need to determine number of students pre-ordered and number of students paid full price.
Let assume number of student pre-ordered year book = x
As out of 24, x students pre-ordered the yearbook , so remaining are the ones who paid full price
So number of students paid full price =
Money spent by students who pre-ordered the book = number of student pre-ordered year book multiplied by Cost of 1 pre-ordered year book =
Money spent by students who paid full price = number of students paid full price x Cost of 1 full price year book =
Total price spent by 24 students to purchase year book = Money spent by students who pre-ordered the book + Money spent by students who paid full price
On solving above expression for x, we get
Number of student pre-ordered year book =
Number of students paid full price =
Hence 15 students pre-ordered the year book and 9 students paid full price.