f(x) = -5x^2 - x + 20;
f(3) = -5*3^2 - 3 + 20 = -5*9 - 3 + 20 = -45 - 3 + 20 = -28;
<span>Given a circle with radius r = 8 and a sector with subtended angle measuring 45°, find the area of the sector and the arc length.
They've given me the radius and the central angle, so I can just plug into the formulas. For convenience, I'll first convert "45°" to the corresponding radian value of π/4:
A = ((pi/4)/2)(8^2) = (pi/8)(8^2) = 8pi, s = (pi/4)(8) = 2pi
area A = 8π, arc-length s = 2π
Given a sector with radius r = 3 and a corresponding arc length of 5π, find the area of the sector.
For this exercise, they've given me the radius and arc length. From this, I can work backwards to find the subtended angle.
Then I can plug-n-chug to find the sector area.
5pi = (theta)(3), (theta) = (5/3)pi
So the central angle is (5/3)π.
Then the area of the sector is:
A = ((5/3)pi / 2)*(3^2) = ((5/6)pi)*(9) = (15/2)pi
A = (15 pi) / 2
</span><span>90/360 = 0.25 pi sq ft</span>
7 x 110 = 7(50 + 60) = 350 + 420 = 770
Answer:
I can't see the graph.....
Step-by-step explanation:
5/10 bc it is equal to 1/2 which is bigger than 2/5 or 4/10 1/3
