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3 years ago

Solve for X:-1 Plz help

Mathematics

2 answers:

irina [24]3 years ago

7 0

Answer:

2nd option

Step-by-step explanation:

-1 < x + 3 < 5

Subtract 3 from both sides;

-4 < x < 2

elena55 [62]3 years ago

4 0

Answer:

Lo siento, solo necesitaba los puntos

Step-by-step explanation:

Lo siento, solo necesitaba los puntos

Lo siento, solo necesitaba los puntosvv

Lo siento, solo necesitaba los puntos

Lo siento, solo necesitaba los puntosvvv

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Miguel deposits $2000 into a bank account that earns simple interest. He writes the expression 2000 + 2000(0.015)(t/12) to repre

oee [108]

Answer:

based on the equation he would make $2.5 in the first month but realistically he would earn around $30 in the first month

Step-by-step explanation:

2000+2000(.015)(1/12)=2002.5

2002.5-2000=2.5

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3 years ago

Chase is making a cake for his daughter's birthday. The normal recipe calls for 8 ounces of butter and 16 ounces of sugar. Chase

kotykmax [81]

Answer:

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Step-by-step explanation:

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3 years ago

According to data from the state blood program, 40 percent of all individuals have group A blood. If six individuals give blood,

Serjik [45]

Answer: 0.27648

Step-by-step explanation:

Given : The proportion of all individuals have group A blood : p=0.040

Total individuals give blood : n= 6

Let X be the number of individuals have group A blood.

Since all individual are independent of each other.

$X\sim Bin(n=6, p=0.40)$

Formula : $P(X=x)=^nC_xp^x(1-p)^{n-x}$ , where n= sample size , p = probability of getting success in each trial.

The probability that exactly three of the individuals have group A blood. :

$P(x=3)= ^6C_3(0.40)^3(1-0.4)^3\\\\= \dfrac{6!}{3!3!}\times(0.40)^3(0.60)^3\\\\=0.27648$

The probability that exactly three of the individuals have group A blood. is 0.27648

8 0

3 years ago

Find the 76th term of the arithmetic sequence 16, 14, 12, ...

skelet666 [1.2K]

Answer:

-134

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

HELPPPPP!!!! MEEE!!! PLEASE!!! ASAPPP!!!!

mario62 [17]

Umm, what grade are you in . i’ll see if i can help

6 0

3 years ago