The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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I think X is 2. But I am not sure, cuz I don’t know what you teacher is really asking you to do.
Can you take the quantity [ x + y ] and square it ?
Can you take the quantity [ x + 2y ] and square it ?
Then you should have no trouble with the square of (.9x + .8y) .
The square of any binomial (expression with 2 terms) is
(square of the first term)
+ (square of the second term)
+ 2 times (product of the terms) .
