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anyanavicka [17]
3 years ago
9

You have 4/3 chocolate bars. You want to give 1/2 of the chocolate bars you have to your friend. What fraction of the chocolate

bars would each of you get
Mathematics
2 answers:
V125BC [204]3 years ago
8 0
2/3 since u just divide the numerator by 2
Crank3 years ago
4 0
The answer would be 2/3
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The sum of two numbers is 57. The larger number is 11 more than the smaller number. What are the numbers?
FromTheMoon [43]

Answer:

I'll tell u later

Step-by-step explanation:

Small number =x

Large number =11 plus x

Now from the question,

x + 11 + x = 57

Therefore 2x plus 11= 57

2x= 57-11=46

X=46÷2=23

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Which decimal is equivalent to<br> 4/20
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The answer should be .20
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In triangle ABC , M and N are midpoints of sides. If MN = 2x + 5 and BC = x2 − 2, find the possible lengths for MN.
Karo-lina-s [1.5K]

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A.17

Step-by-step explanation:

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Simplify the expression:<br> 7x2–5x2<br><br> i need the answer quickly
soldier1979 [14.2K]

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2x^2

Step-by-step explanation:

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A water balloon slingshot launches its projectiles essentially from ground level at a speed of 25.5 m/s . (You can ignore air re
lozanna [386]
A) The longest horizontal distance is reached at 45 degrees angle. This is true for any projectile launch.

B) First, calculate fligth time (using the vertical motion) and then calculate the horizontal movement.

Flight time = 2* ascendent time

ascendent time => final vertical velocity, Vy, = 0

sin(45) = Voy / Vo => Voy = Vosin(45) = 25.5 m/s * (√2) / 2 = 18.03 m/s

Vy = Voy - gt = 0  => Voy = gt = t = Voy / g

Use g = 10 m/s^ (it is an aproximation, because the actual value is about 9.81 m/s^2 depending on the latitud)

t = 18.03 m/s / 10 m/s^2 = 1.83 s

This is the ascendant time going upward.

The flight time is 2*1.83 = 3.66 s

Horizontal motion

Horizontal velocity = Vx = constant = Vox = Vo*cos(45) = 18.03 m/s

Vx = x / t => x = Vx*t

Horizontal distance = xmax = 18.03m/s*3.66 s = 65.99 m

c) The time the ballon will be in the air was calculated in the part B, it is 18.03 s
5 0
4 years ago
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