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Zigmanuir [339]
3 years ago
8

sort these elements into pairs that would most likely exhibit similar chemical properties. Li, K, O, He, Se Ar

Chemistry
2 answers:
kakasveta [241]3 years ago
8 0

Answer:

Li at K may parehong mga chemical katangian O at se parehong mga chemical katangian siya at ar may parehong mga chemical katangian

Explanation:

nexus9112 [7]3 years ago
5 0

<em>Answer:</em>

  •                              Li and  K have same chemical properties
  •                             O and Se have same chemical properties
  •                             He and Ar have same chemical properties

<em>Explanation:</em>

According to modern periodic table, the elements present into same group group have same chemical properties due to same valence shells electrons.

   <em> Li and  K have same chemical properties: </em>

Both these elements are present in same group i.e group 1 known as alkali atoms. Almost all alkali metals have same chemical properties.

    <em> O and Se have same chemical properties</em>

Both these elements are present in same group VI A. The elements present in same group have same chemical properties.

    <em>He and Ar have same chemical properties</em>

Both these elements are present in same group VIII A called it noble gases. The elements present in same group have same chemical properties both are inert.

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A cube has a height of 8 cm and a mass of 457 g. What is its density?
ZanzabumX [31]

Answer:

the answer is b,  0.89

Explanation:

A cube has a height of 8 cm and a mass of 457 g. What is its density?

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b.  0.89g/cm3

c. 1.12 g/cm3

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3 0
2 years ago
Cl2(g) + 2kBr(s) ---&gt; 2KCl(s) + Br2(g) Rewrite the equation and write the color of each chemical under its name. 2. What type
kolezko [41]

Answer:

Cl2(g) (green/yellow mix) + 2KBr(s) (white) ---> 2KCl(s) (violet) + Br2(g) (reddish brown)

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Explanation:

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8 0
3 years ago
Determine the percent water in MgSO4*7H20?
Semmy [17]

Answer:

\% H_2O=51.2\%

Explanation:

Hello!

In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:

MM_{MgSO_4* 7H_2O}=120.36 g/mol+7*18.02g/mol\\\\MM_{MgSO_4* 7H_2O}=246.5g/mol

Thus, the percent water is:

\% H_2O=\frac{7*MM_{H_2O}}{MM_{MgSO_4* 7H_2O}} *100\%\\\\

So we plug in to obtain:

\% H_2O=\frac{7*18.02}{246.5} *100\%\\\\\% H_2O=51.2\%

Best regards!

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3 years ago
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