4 examples of bases
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Answer:
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The reaction is as follows:
2 H₂(g) + O₂(g) → 2 H₂O(g) . ΔH = - 483.5 kJ
Using the change in enthalpy and heat, calculate the moles as follows:
Moles of H₂ = -
x 2 mol H₂
= - 216 kJ / (-483.5 kJ) x 2 mol H₂
= 0.893 mol H₂
Calculate the mass of H₂ using the moles and molar mass as follows:
0.893 mol H₂ x (2.02 g H₂ / 1 mol H₂) = 1.79 g H₂
Therefore, the mass of hydrogen gas is 1.79 g
2 H₂(g) + O₂(g) → 2 H₂O(g) . ΔH = - 483.5 kJ
Using the change in enthalpy and heat, calculate the moles as follows:
Moles of H₂ = -
= - 216 kJ / (-483.5 kJ) x 2 mol H₂
= 0.893 mol H₂
Calculate the mass of H₂ using the moles and molar mass as follows:
0.893 mol H₂ x (2.02 g H₂ / 1 mol H₂) = 1.79 g H₂
Therefore, the mass of hydrogen gas is 1.79 g
Number of moles of sodium reacted is 2 moles. 0.04598 Kg is the mass of sodium that reacted.
Mole fraction is 1 mole ratio is 1:1
Explanation:
Balanced chemical reaction:
2 Na + 2H20 ⇒ 2NaOH + H2 (gas)
atomic mass of sodium = 22.99 g/mol
from the reaction it can be seen that 2 moles of sodium reacted to form 2 moles of sodium hydroxide soluition.
The mass of sodium reacted can be calculated from the formula:
mass = atomic mass of one mole x number of moles
mass = 22.99 x 2
= 45.98 grams is the mass of sodium, to convert it into kilograms it is divided by 1000
= 0.04598 Kg is the mass of sodium that reacted.
Mole fraction formula is:
= mole fraction ( solute Na = 2 moles, solution is NaOH =2 moles)
putting the values:
= 1 mole ratio is 1:1