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igomit [66]
2 years ago
13

The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:

Chemistry
1 answer:
Lera25 [3.4K]2 years ago
3 0

The allowable combination for the atomic orbital is n=4, l=2, m_{l}=2.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; m_{l} values are integers from -l to =l(l limits ml)

For n = 4, l can four values: 0, 1, 2, and 3. To be consistent with m_{l}=+2the l value must be higher than 1. There are two l values that are consistent with n and m_{l} values:  l= 2 or 3

Therefore, the allowable condition is n=4, l=2, m_{l}=2

To know more about quantum numbers, visit: brainly.com/question/16979660

#SPJ4

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Explanation:

Hello,

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For example, the oxidation state of Cr in Cr_{2}O^{2-}_{7} is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.

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