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Kaylis [27]
4 years ago
14

Hard math please help.

Mathematics
1 answer:
zvonat [6]4 years ago
8 0

Answer:

Step-by-step explanation:help me first

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My name is Ann [436]

Answer: I think b

Step-by-step explanation:

5 0
3 years ago
If you are starting with what you know about a large population and coming to a conclusion about a specific scenario, then which
Ostrovityanka [42]

Answer:

Education –> Mortality –> Fertility rates

Education –> Fertility rates

Step-by-step explanation:

Education and fertility is a key role to grow a large population. But if the mortality rate is low families tend to have less children.

4 0
3 years ago
Elena is buying cups and plates for her party. Cups are sold in packs of 8 and plates are sold in packs of 6. She wants to have
Svet_ta [14]

Answer:

For 80 people, Elena would need

14 packs of plates and 10 packs of cups

She would have at least 80 of each.

I am not completely sure of this, sorry if wrong.

Step-by-step explanation:

80 people

8 cups per pack

6 plates per pack

8, 16, 24, 32, 40, 48, 56, 64, 72, 80

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84

LCM (least common multiple) = 24

8 0
3 years ago
Read 2 more answers
A rectangle is 12 ft long and 34 ft wide. What is the area of the rectangle?
aksik [14]
A=Lw
The area is 12*34, 408 sq ft.
4 0
4 years ago
Read 2 more answers
The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
Anettt [7]

Answer:

1) The size of the colony after 4 ​days is 6553 mosquitoes

2) After t = 4.9\ days

Step-by-step explanation:

To answer this question you must use the growth formula

N = N_0e ^ {kt}

Where

N_0 is the initial population of mosquitoes = 1000

t is the time in days

k is the growth rate

N is the population according to the number of days

We know that when t = 1 and N_0=1000 then N = 1600

Then we use these values to find k.

1600 = 1000e ^{k(1)}\\\\\frac{1600}{1000} = e ^ k\\\\ln(\frac{1600}{1000}) = k\\\\k = 0.47

Now that we know k we can find the size of the colony after 4 days.

N = 1000e ^ {0.47(4)}\\\\N = 6553\ mosquitoes

To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

10000 = 1000e ^ {0.47t}\\\\10 = e ^ {0.47t}\\\\ln(10) = 0.47t\\\\t = \frac{ln(10)}{0.47}\\\\t = 4.9\ days

6 0
3 years ago
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