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Rashid [163]
2 years ago
12

Find the area of the shaded portion in the equilateral triangle with sides 6.

Mathematics
1 answer:
VashaNatasha [74]2 years ago
3 0
First, let's get the area of the entire triangle since we'll need it later. The area of a triangle is A=1/2*b*h

We can find the height with the Pythagorean theorem by splitting the triangle in half. 
3^2+b^2=6^2
9+b^2=36
b^2=27
b=√27

Then we can find the area:
A=1/2*6*√27
A=3√27   or   =9√3   or 15.59

Now we can find the area of each region in the triangle other than the shaded region because they are all portions of a circle.

Each region has an angle of 60 because this is an equilateral triangle. Therefore the area of each region other than the shaded region will be 1/6 the area of a circle with a radius of 3 because a full circle is 360 degrees.
A=pi*r^2/6
A=pi*9/6
A=4.71

So three of these regions would have an area of 14.14

We do the area of the triangle minus the area of these regions to get the area of the shaded region
15.59-14.14 = 1.45

Hope this helps!


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To add fractions you want to make sure that the bottom numbers are the same so we have to make them the same, but we have to make sure that the fractions are unchanged so we get the correct answer

so if we find out what number that 9,7, and 5 can all multiply into. we find that 9 times 7 times 5 or 315 is the number that will work

so to get them to all be over 315, we must multiply each fraction by a form of 1/1 or x/x or (number)/(same numbe as on top)

so 7/9 times (35/35)=245/315
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we add them togther
245/315+45/315+168/315=(245+45+168)/315=458/315
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We would first, by orders of operation, multiply the -1 and the -3 getting 3.  Then the problem would simplify down to -2 + 3

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Step-by-step explanation:

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