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3 years ago

12

Graph the solution of 2 ≥ 4 - v

2 answers:

Lerok [7]3 years ago

6 0

For this case we have the following inequality:
2 ≥ 4 - v
The first thing we must do in this case is to clear the value of v.
We have then:
v ≥ 4 - 2
v ≥ 2
Therefore, the solution set is given by:
[2, inf)
Answer:
See attached image.

Rainbow [258]3 years ago

6 0

Answer:

Ok so ppl it just A

Step-by-step explanation:

To solve this problem, we must first subtract 4 from both sides of the inequality. This gives us -2 ≥ -v. Next divide both sides by -1. Remember, when you divide by a negative in an inequality, it becomes necessary to flip the direction of the inequality symbol. Therefore, the answer to the inequality is 2 ≤ v, which is equivalent to v ≥ 2.

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Translate the abgebraic expression into a verbal pharse 2x-4

Afina-wow [57]

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3 years ago

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Zoe works in a bakery. She uses 250 milliliters of milk to make a loaf of bread. How many liters of milk will she need to make 1

bonufazy [111]

Answer: 3.75 liters

Step-by-step explanation:

Zoe uses 250 milliliters of milk to make a loaf of bread.

If she needed to make 15 loaves therefore, she would do the following:

= 250 * 15 loaves

= 3,750 milliliters of milk

Then convert the above quantity to liters.

1 Liter = 1,000 milliliters.

3,750 milliters to liters is:

= 3,750 / 1,000

= 3.75 liters

3 0

2 years ago

If ΔABC ΔDEC, what is m∠D? A. 40° B. 150° C. 60° D. 80°

Nina [5.8K]

I think that the best answer here would be that A = 40 degrees.

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=Factor%3A%20x%5E2-9" id="TexFormula1" title="Factor: x^2-9" alt="Factor: x^2-9" align="absmidd

Bezzdna [24]

Answer:

x²-9=x²-3²=(x+3)(x-3)

Step-by-step explanation:

use formula

a²-b²=(a+b)(a-b)

7 0

2 years ago

Which classification describes AMNO with vertices M(2, -3), N(3, 1), and<br> 0(-3, 1)?

Sonja [21]

Answer:

Option D

Step-by-step explanation:

32). Given vertices of the triangle are M(2, -3), N(3, 1) and O(-3. 1).

Distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the expression,

Distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between M(2, -3) and N(3, 1) will be,

MN = $\sqrt{(3-2)^2+(1+3)^2}$

= $\sqrt{1+16}$

= $\sqrt{17}$

Distance between M(2, -3) and O(-3, 1),

MO = $\sqrt{(2+3)^2+(-3-1)^2}$

= $\sqrt{25+16}$

= $\sqrt{41}$

Distance between N(3, 1) and O(-3, 1),

NO = $\sqrt{(3+3)^2+(1-1)^2}$

= 6

Condition for right triangle,

c² = a² + b² [Here c is the longest side of the triangle]

By this property,

MO² = MN² + NO²

$(\sqrt{41})^2=(\sqrt{17})^2+6^2$

41 = 17 + 36

41 = 51

False.

Therefore, given triangle is not a right triangle.

Since, length of all sides are not equal, given triangle will be a scalene triangle.

Option D is the correct option.

5 0

3 years ago