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frozen [14]
3 years ago
9

What is the missing number in the input output table

Mathematics
2 answers:
MakcuM [25]3 years ago
8 0

Answer:

input is 3 5 9 17 so hope you get the answer thanks

Llana [10]3 years ago
7 0
3, 5 , 7 , 9
good luck !
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Um litro de suco é dividido entre três amigos. O primeiro fica com 14 do todo, o segundo fica com 1/3 do total e o terceiro fica
kkurt [141]

Answer:

a) 1/24 do total

Step-by-step explanation:

We have that:

The total is 1.

The first friend gets 1/4 of the total.

The second friend gets 1/3 of the total

The third friend gets 3/8 of the total.

The remaining is x.

So

\frac{1}{4} + \frac{1}{3} + \frac{3}{8} + x = 1

The least common multiple between 4, 3 and 8 is 24. So

\frac{6 + 8 + 3*3 + 24x}{24} = 1

23 + 24x = 24

24x = 1

x = \frac{1}{24}

So the correct answer is:

a) 1/24 do total

3 0
4 years ago
Only answer #3 please
levacccp [35]

Answer:

-2

Step-by-step explanation:

you would go to wear your line crosses you y-axis, which is the vertical one

so it crosses at -2

7 0
3 years ago
Read 2 more answers
order the numbers from least to greatest
Nuetrik [128]

Answer:

-7/3 < -3/4 < 0.5 < 2/3 < 1.2

Step-by-step explanation: Heres your answer. Sorry if its wrong.

7 0
3 years ago
Kim wants to determine a 90 percent confidence interval for the true proportion of high school students in the area who attend t
PolarNik [594]

Answer:

We need a sample of at least 752 students.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large of a sample must she have to get a margin of error less than 0.03

We need a sample of at least n students.

n is found when M = 0.03.

We have no information about the true proportion, so we use \pi = 0.5.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.645*0.5

\sqrt{n} = \frac{1.645*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.645*0.5}{0.03})^{2}

n = 751.67

Rounding up

We need a sample of at least 752 students.

6 0
4 years ago
870 mg sodium is 30% of recommended daily allowance. What is the recommended daily allowance
Sedbober [7]
The recommended daily allowance is 2,900 Mg. 2,900 times .3 (decimal form of 30%) will give you 870 Mg
5 0
3 years ago
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