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3 years ago

Please help!! I really don't want to get this one question wrong and mess up my score :(

Mathematics

2 answers:

Elan Coil [88]3 years ago

7 0

Answer:

12^9 is the correct answer to the question

Step-by-step explanation:

12^8+(-)8-(-)9=8-8+9=9

12^9

Ket [755]3 years ago

3 0

Answer:

12^9

Step-by-step explanation:

12^8 * 12^-8

according to law of integers, since both numbers are the same we can work with their roots, and the multiplication would be addition;

8+(-8)= 0

(12*12)^0 ----numerator

(denominator)

12^-9

division = subtraction in the laws of integers

0-(-9)= 0+9=9

(12*12)/12= 12

=12^9

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Question in photo too lazy to solve lol

Tamiku [17]

The value of 3centimeters to kilometers is 0,00003 km

<h3>Converting centimeters to meters</h3>

In order to convert centimeters to kilometers, we will use the conversion factor below.

100cm = 1m

1000m = 1km

Given 3cm

3cm = 3/100 m

3cm = 0.03m

Convert to km

Since 1000m = 1km

0.03m = 0.03/1000

0.03m = 0.00003km

Therefore the value of 3centimeters to kilometers is 0,00003 km

Learn more on cm to km here: brainly.com/question/1549097

#SPJ1

3 0

2 years ago

pls help I’ll brainlest and add extra points

mario62 [17]

he is not well so I am not able to join the meeting and I am not able to join the meeting and I am not able to join the

5 0

3 years ago

Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random

Katen [24]

Answer:

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

Step-by-step explanation:

Given

$n = 200$

$x_1 = 34$ -- City C

$x_2 = 54$ --- City K

Required

Determine the 90% confidence interval

This is calculated using:

$CI = \bar x \± z\frac{\sigma}{\sqrt n}$

Calculating $\bar x$

$\bar x = \bar x_1 - \bar x_2$

$\bar x = \frac{x_1}{n} - \frac{x_2}{n}$

$\bar x = \frac{34}{200} - \frac{54}{200}$

$\bar x = 0.17 - 0.27$

For a 90% confidence level, the z-score is 1.65. So:

$z = 1.65$

Calculating the standard deviation $\sigma$

$\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }$

So:

$\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }$

$\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}$

So:

$CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}$

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

7 0

3 years ago

on the first of january 2014, carol invested some money in a bank account. The account pays 2.5% interest per year. On the first

almond37 [142]

Answer: £23,360

Step-by-step explanation:

You can use algebra to solve this.

Assume that the original investment is x.

In the beginning of 2015 the balance had increased by 2.5% which is denoted as:

= 1.025x

Carol then withdrew a thousand:

= 1.025x - 1,000

This value then increased by 2.5% again by the beginning of 2016:

= 1.025 * (1.025x - 1,000)

Relevant expression therefore is:

1.025 *(1.025x - 1,000) = 23,517.60

1.025x - 1,000 = 23,517.60/1.025

1.025x = ‭22,944‬ + 1,000

x = 23,944/1.025

x = £23,360

8 0

3 years ago

What's one fifth of 45

pishuonlain [190]

1 /5 = 0 . 2
45 * . 2 = 9
Hope this helped :)

3 0

4 years ago

Read 2 more answers