I hope this helps you
distance=speed×time
first cars time t
second cars time t+3
same distance
distance=55.t
distance=40. (t+3)
55t=40 (t+3)
55t-40t=120
15t=120
t=8
t+3=11
So to factor
factor out a x+z
(x+z)(x^2-xz+z^2)
the factors are
x+z and x^2-xz+z^2
Each side is equal its in the name. hope this help!!
a square as the distance between the lengths and widths are 3
-13 and -14
They both are consecutive negative integers that multiply to 182.
