Answer:
of gravel was used.
Step-by-step explanation:
Given that,
The height of a cone, h = 6 feet
The diameter of the base of cone, d = 8.2 feet
Radius, r = 4.1 feet
We need to find the amount of gravel was delivered. The volume of a cone is given by :

So,
of gravel was used.
First part of the race
speed1, s1 = 8.75 km/h
distance1 = 5 km - x
time 1 = 0.65 h - t
Second part of the race
speed2, s2 = 6 km/h
distance2 = x
time2 = t
s2 = x/t = 6 ⇒ t = x / 6
s1 = [5 - x] / [0.65 - t] = 8.75
5 - x = 8.75 [0.65 - t]
5 -x = 8.75(0.65) - 8.75t
5 - x = 5.6875 - 8.75 (x/6)
5 - x = 5.6875 - 1.4583x
1.4583 x - x = 5.6875 - 5
0.4583 x = 0.6875
x = 0.6875 / 0.4583 = 1.5
Okay so yes for the first one it is 4 Sig digs
And I believe you are correct on the 2nd one.. I beleive it is also D.
Go with your gut! And good luck! :D