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3 years ago

Glenda wrote 1/7 of her paper on Monday, 1/ 14 of her paper on Tuesday, and 2/28 of

Mathematics

2 answers:

Art [367]3 years ago

5 0

Answer:

1/7x 4/4 = 4/28

1/14x 2/2= 2/28

1/28

total

7/28= 1/4

Step-by-step explanation:

Pie3 years ago

3 0

No, she is not correct; you need to make all of the denominators the same by finding the highest common factor.
The highest common factor of all of these is 28, so you must multiply each numerator by however much you multiplied the denominators. So:
1/7 x 4 = 4/28
1/14 x 2 = 2/28
2/28 x 1 = 2/28
Now you need to add all of these, which would be 6/28.
6/28 is less than half, so she is not correct.

Hope this helps

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Which graph shows that Cindy reads about 3/4 of the time while riding in the car?

wolverine [178]

The graph that shows a unit rate of 3/4, which is the time Cindy reads while riding in the car is the graph attached below.

Unit rate can be described as a constant or exactly how much of one quantity is per 1 unit of another quantity.

Unite rate (k) = x/y.

In the graph attached below, when x (hours driving) = 3, y (hours reading) = 4.

Therefore, unit rate = 3/4. We can then conclude that the graph that shows that Cindy reads 3/4 of the time she rides in a car is the graph attached below.

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2 years ago

If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.

galina1969 [7]

Answer:

$\frac{\frac{1000}{x+h}-\frac{1000}{x}}{h}$ is your average rate of change,

Step-by-step explanation:

average rate of change is

$\frac{f(a+h)-f(a)}{a+h-a}$ , by slope formula

simplify this to get $\frac{f(a+h)-f(a)}{h}$ , which is the definition of the derivative as h goes to 0

$\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}$

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

$\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}$

simplifying

$\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h}$ (your average rate of change)

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3 years ago

Two factors of 24 that add up to 11

Vadim26 [7]

Simple....

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Thus, your answer.

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Arlecino [84]

We know that
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so
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therefore
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if the

average per minute = (18/55) pizzas /minute
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zloy xaker [14]

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