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3 years ago

Glenda wrote 1/7 of her paper on Monday, 1/ 14 of her paper on Tuesday, and 2/28 of

Mathematics

2 answers:

Art [367]3 years ago

5 0

Answer:

1/7x 4/4 = 4/28

1/14x 2/2= 2/28

1/28

total

7/28= 1/4

Step-by-step explanation:

Pie3 years ago

3 0

No, she is not correct; you need to make all of the denominators the same by finding the highest common factor.
The highest common factor of all of these is 28, so you must multiply each numerator by however much you multiplied the denominators. So:
1/7 x 4 = 4/28
1/14 x 2 = 2/28
2/28 x 1 = 2/28
Now you need to add all of these, which would be 6/28.
6/28 is less than half, so she is not correct.

Hope this helps

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It takes you 5 hours to complete a 375-kilometer trip. What was your average speed on this trip?

morpeh [17]

Answer:

Step-by-step explanation:

V=S/T(the formula)

V= 375/5

V=75

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3 years ago

Read 2 more answers

While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at

tekilochka [14]

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>

Let x be the speed of the walkway.

(2.8 + x) = speed of child moving in direction of the walkway

(2.8 - x) = speed of child moving against the direction of the walkway

Travel time = distance/speed

Travel time of child moving in direction of walkway = 23/(2.8+x)

Total elapsed time given = 29s

23/(2.8 + x)+ 23 / (2.8-x) = 29

LCD = (2.8 + x)(2.8 - x)

$23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)$

simplifying the equation, we get

$23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)$

$23(2.8+2.8)/29=2.8^2-x^2$

$x^2=(2.8)^2-(23*5.6)/29)=3.4$

$x=\sqrt{3.4}=1.84m/s$

Speed of walkway = 1.84 m/s

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

To learn more about Speed refer to:

brainly.com/question/4931057

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2 years ago

A 10ft by 10ft square garden contains a large walking path through the diagonal. What is the area of the walking path shown in t

SpyIntel [72]

64fts^2 is the answer

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3 years ago

Help me please I need this done quick

Anna11 [10]

Answer:
1058.4 in^2

Step-by-step explanation:
Find the surface areas of the rectangular prism and the triangular prisms separately.
Triangular: S = (1/2)lP+B, where l is slant height, P perimeter, and B base area.
14(4)= 56 perimeter of base
13 slant height
B = 14x14 = 196
put together:
S = (1/2)(13 x 56) + 196
S = 560 in^2

Now the rectangular prism
S = 2lw + 2lh + 2wh, where l is length, h height, w width. (delete the first 2lw since they share one side/they're combined shapes.
S = 2(14x8.9) + 2(14x8.9)
S = 498.4 in^2

Add them together: 498.4 + 560 = 1058.4 in^2

7 0

2 years ago

What is 45,231 written in expanded form? 2 x 10,000 + 1 x 1,000 + 3 x 100 + 5 x 10 + 4 2 x 10,000 + 3 x 1,000 + 1 x 100 + 4 x 10

adoni [48]

Answer:

45231 = $4 \times 10000 + 5\times 1000 +2 \times 100 + 3\times 10 +1 \times 1$

Step-by-step explanation:

Given the number:

45,231

We have To write the given number in the expanded form.

Solution:

First of all, let us write the different digits of the number:

Unit's digit = 1

Ten's digit = 3

Hundred's digit = 2

Thousand's digit = 5

Ten thousand's digit = 4

Unit's digit has to be multiplied with 1.

Ten's digit has to be multiplied with 10.

Hundred's digit has to be multiplied with 100.

Thousand's digit has to be multiplied with 1000.

Ten Thousand's digit has to be multiplied with 10000.

And then they have to be added so that the number gets formed.

45231 = $4 \times 10000 + 5\times 1000 +2 \times 100 + 3\times 10 +1 \times 1$

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3 years ago