You run one lap around a mile track every 8 minutes. Your friend runs around the same track every 10 minutes. You both start at
1 answer:
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The initial value is 3 (when x=0), and the multiplier is 2, when x=2. The equation can be written as
.. y = 3*(2^(x/2))
.. y = 3*(2^(x/2))
With 
, the Fourier series expansion of 
is
where the coefficients are obtained by computing
You should end up with
(both due to the fact that is odd)
Now the problem is that this expansion does not match the given one. As a matter of fact, since is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.
One possibility is that you're actually supposed to use the even extension of, which is to say we're actually considering the function
and enforcing a period of
. Now, you should find that
The value of the sum can then be verified by choosing
, which gives
as required.
where the coefficients are obtained by computing
You should end up with
(both due to the fact that
Now the problem is that this expansion does not match the given one. As a matter of fact, since
One possibility is that you're actually supposed to use the even extension of
and enforcing a period of
The value of the sum can then be verified by choosing
as required.
Answer:
Step-by-step explanation:
Notice that function has the exat shape of function
, and it has just be translated to the right by 3 whole units.
Recall that horizontal translations to the right involve subtracting the number of units moved in the translation from the variable "x". therefore, in our case this means: