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Yanka [14]
3 years ago
13

Write a number or expression in each blank space to create true equations.

Mathematics
1 answer:
Rina8888 [55]3 years ago
4 0

Answer:

7(3+5)=7(3)+7(5)\\15-10=5(3-2)

Step-by-step explanation:

Both expressions are examples of the <em>distributive property</em>, which basically says "if I have <em>this </em>many groups of some size and <em>that</em> many groups of the same size, I've got <em>this </em>+ <em>that</em> groups of that size altogether."

To give an example, if I've got <em>3 groups of 5 </em>and <em>2 groups of 5</em>, I've got 3 + 2 = <em>5 groups of 5 </em>in total. I've attached a visual from Math with Bad Drawings to illustrate this idea.

Mathematically, we'd capture that last example with the equation

5(3)+5(2)=5(3+2). We can also read that in reverse: 3 + 2 groups of 5 is the same as adding together 3 groups of 5 and 2 groups of 5; both directions get us 8 groups of 5. We can use this fact to rewrite the first expression like this: 7(3+5)=7(3)+7(5).

This idea extends to subtraction too: If we have 3 groups of 4 and we take away 1 group of 4, we'd expect to be left with 3 - 1 = 2 groups of 4, or in symbols: 4(3)-4(1)=4(3-1)=4(2). When we start with two numbers like 15 and 10, our first question should be if we can split them up into groups of the same size. Obviously, you could make 15 groups of 1 and 10 groups of 1, but 15 is also the same as <em>3 groups of 5</em> and 10 is the same as <em>2 groups of 5</em>. Using the distributive property, we could write this as 15-10=3(5)-2(5)=5(3-2), so we can say that 15-10=5(3-2).

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Step-by-step explanation:

Permutation :The number of ways to choose a sample of r elements from a set of n distinct objects where order does matter and replacements are not allowed.

                                  nPr = \frac{n!}{(n-r)!}

Factorial : There are n! ways of arranging n distinct objects into an ordered sequence.  

Considering a situation when n = r in a permutation, nPr reduces to n!, a simple factorial of n.

Proof: 3P3 = 3!

n = 3 and r = 3

                                   3P3 = \frac{3!}{(3-3)!}

                                   3P3 = \frac{3!}{(0)!}

But 0! = 1

                                    3P3 = 3!

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3 years ago
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The first aquarium has 100 small fish.

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The second aquarium has 40 large fish.

100small fish+40 large fish=140 total fish
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Order the following numbers from greatest to least: 7.321, 7.3, 7.065, 7.65
Slav-nsk [51]

The order for the given decimal numbers, from the greatest to the least, is: D. 7.65, 7.321, 7.3, 7.065.

<h3>How to Order a Set of Decimal Numbers?</h3>

When considering the order of a set of decimal numbers, the value larger the digit that is close to the decimal point, the larger the decimal number, and vice versa.

Given the following set of decimal numbers, 7.321, 7.3, 7.065, 7.65.

Notice that all decimal numbers start with 7. So, the digit close to the decimal point is what we will consider to determine which decimal number is greater or the least.

The decimal number that has the greater digit that is close to the decimal point is, 7.65, followed by 7.321, then 7.3.

The decimal number with the least digit closer to the decimal point is 7.065.

Therefore, the order for the given decimal numbers, from the greatest to the least, is: D. 7.65, 7.321, 7.3, 7.065.

Learn more about order of decimal numbers on:

brainly.com/question/20603315

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