This employee who was randomly chosen represents the population of the company. This means that, any parameter measured through this employee can be considered as the mean or average value for the whole population (the company).
Based on this, taking the age of the employee as the desired parameter, the age of this employee will be considered as the average or mean age for the whole company. This means that the age of the employee and the mean age of all employees are equal.
Therefore, the answer is C) 32, 32
<span>An employee was randomly chosen from a company. If the expected value of the age of the employee is 32 years old, the mean age of all the employees in the company is 32 years old.</span>
65 sequences.
Lets solve the problem,
The last term is 0.
To form the first 18 terms, we must combine the following two sequences:
0-1 and 0-1-1
Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent
So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:
2x + 3y = 18
Case 1: x=9 and y=0
Number of ways to arrange 9 identical 2-term sequences = 1
Case 2: x=6 and y=2
Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28
Case 3: x=3 and y=4
Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35
Case 4: x=0 and y=6
Number of ways to arrange 6 identical 3-term sequences = 1
Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65
Hence the number of sequences are 65.
Learn more about Sequences on:
brainly.com/question/12246947
#SPJ4
Answer:
Graph B is correct
Step-by-step explanation:
Answer:
1/4 of 10 is 2 1/2
then 7 1/2 is left
