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3 years ago

8

The cost of renting a car is $40 plus an additional $0.60 for each mile driven.write an expression to represent the cost of rent

ing a car for x miles.

1 answer:

lesya [120]3 years ago

5 0

Answer:

40+0.60x=total

Step-by-step explanation:

You might be interested in

Slope of (-7,-2) (9,4)

Olenka [21]

Answer:

m= $\frac{3}{8}$

Step-by-step explanation:

1. Use the slope equation to solve the problem

$\frac{y_{2} -y_{1}}{x_{2} -x_{1} }$

2. Plug in your values into the equation.

$\frac{4-(-2)}{9-(-7)}$

3. Simplify the equation.

m= $\frac{3}{8}$

4 0

3 years ago

Please show an actual answer i need help

jek_recluse [69]

Answer:

1. wire is approx. 143.96 ft

2. pole is approx. 106.55 ft

Step-by-step explanation:

Mapping the information on the SOHCAHTOA picture below:

Φ = 46

wire = hypotenuse

adjacent side = 100

CAH is most suitable:

cos 46° = 100/wire => wire = 100/cos 46 ≈ 143.96

pole = opposite side + 3

TOA is most suitable:

tan 46° = (pole-3)/100 => pole = 3 + 100 * tan 46 ≈ 106.55

4 0

3 years ago

A gray crayon is made with 5\text{ mL}5 mL5, space, m, L of black wax for every 6\text{ mL}6 mL6, space, m, L of white wax.

zloy xaker [14]

The correct answers are B and C.

Since the mixture requires 5 mL of black wax and 6 mL of white wax, we want multiples of these numbers; specifically, we need multiples that are the same number of times away.

A does not work; 10 is 5*2 and 24 is 6*4. These won't be in the same ratio.

B works; 15 is 5*3 and 18 is 6*3. These have the same ratio.

C works; 35 is 5*7 and 42 is 6*7. These have the same ratio.

D does not work; 26 is not a multiple of 6.

E does not work; 45 is 5*9 and 48 is 6*8. These will not have the same ratio.

8 0

3 years ago

Read 2 more answers

Describe how the graph of the second function relates to the graph of the first function. y = |x| y = |x| − 3

tresset_1 [31]

Step-by-step explanation:

y=|x| is a vee graph starting at (0,0)

y=|x| - 3 is a vee graph starting (0,-3)

see attachment

3 0

3 years ago

If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a

galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

$r1(t)=$

$r2(t)=$

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

$t^2=4t-3$

Rearranging

$t^2-4t+3=0$

Factoring

$(t-1)(t-3)=0$

We found two solutions

$t=1,\ t=3$

for t=1 the x-coordinates are

$x1=t^2=1$

$x2=4t-3=1$

For t=3

$x1=t^2=9$

$x2=4t-3=9$

Now we'll test both values in the y-coordinates

$y1=7t-12$

$y2=t^2$

For t=1

$y1=-5$

$y2=1$

Thus they don't collide at t=1. Let's try t=3

$y1=7(3)-12=9$

$y2=3^2=9$

Now let's try the z-coordinate for t=3

$z1=t^2=9$

$z2=5t-6=9$

Since the three coordinates match, we can say both objects collide at t=3 in the point <9,9,9>

6 0

4 years ago