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Rainbow [258]
3 years ago
13

Solve by substitution 3x+y=3 and 7x+2y=1

Mathematics
1 answer:
balu736 [363]3 years ago
5 0

3x + y = 3

7x + 2y = 1

First isolate one of the variables (x or y) in one of the equations.

Isolate "y" in the first equation(because it is the easiest to isolate) and substitute it into the second equation.

3x + y = 3      Subtract 3x on both sides

3x - 3x + y = 3 - 3x

y = 3 - 3x


7x + 2y = 1

7x + 2(3 - 3x) = 1     [since y = 3 - 3x, you can substitute (3-3x) for "y"]

Multiply/distribute 2 into (3 - 3x)

7x + (3(2) - 3x(2)) = 1

7x + 6 - 6x = 1

x + 6 = 1     Subtract 6 on both sides

x = -5


Now that you know "x", substitute it into one of the equations (I will do both)

3x + y = 3

3(-5) + y = 3       [since x = -5, you can plug in -5 for "x"]

-15 + y = 3    Add 15 on both sides

y = 18


7x + 2y = 1

7(-5) + 2y = 1

-35 + 2y = 1     Add 35 on both sides

2y = 36     Divide 2 on both sides

y = 18


x = -5, y = 18  or  (-5, 18)

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Find x, y and ab and how to check if the answer is right ​
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Answer:

  x = 2, y = -2, AB = 142

Step-by-step explanation:

The fact that X is the midpoint gives you two relations:

  AX = XB

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Since you have two unknowns, this number of equations is sufficient to find their values. Substituting the given expressions in the above equations, you have ...

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  24x +40 -3y +21 -22x = 5x +y +23 -4x +48

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  x -4y = 10 . . . . . . . . . . . . . . . . subtract x+y+61

Now, we can simplify the second equation to ...

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  3x -2y +132 = 2x -5y +128 . . . . . simplify the left side

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The desired values are x = 2, y = -2, AB = 142.

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