Answer:
Length of the bold arc = 72.63 ft
Step-by-step explanation:
Length of the arc = 
Here, θ = angle subtended by the arc at the center
r = Radius of the circle
Since, angle subtended by the bold arc at the center = 360 - 73
= 287°
And radius of the circle 'r' = 14.5 ft
By substituting these values in the formula,
Length of the bold arc = 
= 72.632
≈ 72.63 ft
Therefore, length of the bold arc = 72.63 ft
Answer:
$395.61
Step-by-step explanation:
The formula for simple interest is:

Where
i is the interest amount
P is the principal amount
r is the rate of interest per time period
t is the time period
Here,
P = 4869
we want to find after 30 months, that converted to years is:
30/12 = 2.5 years
t = 2.5
The annual rate is 3.25% = 0.0325
Now, substituting, we find our answer:

The interest earned is <u>$395.61</u>
#1. The number line goes by intervals of 0.2, so if A is equal to 7.28, then it’ll go in between the first line after 7 and the second line after 7. This is similar with B and C. B will go on the second line after 9, and C will go in between the second and third line after 10.
#3. You started out well. You combine your like terms on the sides of the equation to get 8x - 2 = 4x + 6. Then, you’ll subtract 4x to get 4x - 2 = 6. Add 2 to get 4x =8, then divide by 4 to get x = 2. On the other one, combine your terms to get -6 + 5y = 29. Then, add 6 so you have 5y = 35. Divide by 5 to get y = 7.
#4. When you classify a number, you need to classify it as whatever it is in your disgramdiagram, and the larger ones as well. For example, -2 is an integer, so it is also a rational number. 3/4 is a rational number. The square root of 2 over 2 is an irrational number. 292 is a counting, whole, integer, and rational number. -19/3 is a rational number. 6.9696... is an irrational number. (It has the three dots [...] so it’ll go on forever with no pattern.)
I hope this helps! Please tell me if you need any clarification. :)
The volume of the region R bounded by the x-axis is: 
<h3>What is the volume of the solid (R) on the X-axis?</h3>
If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.
From the given graph:
The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

here:
- (x₁, y₁) and (x₂, y₂) are two points on the straight line
Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8) from the graph, we have:

y = 4x
Now, our region bounded by the three lines are:
Similarly, the change in polar coordinates is:
where;
- x² + y² = r² and dA = rdrdθ
Therefore;
- rsinθ = 0 i.e. r = 0 or θ = 0
- rcosθ = 2 i.e. r = 2/cosθ
- rsinθ = 4(rcosθ) ⇒ tan θ = 4; θ = tan⁻¹ (4)
- ⇒ r = 0 to r = 2/cosθ
- θ = 0 to θ = tan⁻¹ (4)
Then:


Learn more about the determining the volume of solids bounded by region R here:
brainly.com/question/14393123
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