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2 years ago

First five term for An=n^2-2n

Mathematics

1 answer:

densk [106]2 years ago

6 0

First 5 terms are: -1,0,3,8,15

Step-by-step explanation:

we will put n=1,2,3,4,5 to find first 5 terms of the sequence

Explicit formula for sequence is:

$a_n = n^2-2n$

Putting n=1

$a_1 = (1)^2-2(1)\\= 1-2\\= -1$

Putting n=2

$a_2 = (2)^2-2(2)\\= 4 - 4 \\=0$

Putting n=3

$a_3 = (3)^2-2(3)\\= 9-6\\= 3$

Putting n=4

$a_4 = (4)^2 - 2(4)\\= 16-8 \\= 8$

Putting n=5

$a_5 = (5)^2-2(5)\\= 25 - 10\\= 15$

Hence,

First 5 terms are: -1,0,3,8,15

Keywords: Arithmetic sequence, Common difference

Learn more about arithmetic sequence at:

#LearnwithBrainly

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3 years ago

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2 years ago

Calvin had 30 minutes in time-out. For the first 23 1/3 minutes, Calvin counted spots on the ceiling. For the rest of the time,

scoundrel [369]

Answer: $\frac{20}{3}\ minutes$ or $6 \frac{2}{3}\ minutes$

Step-by-step explanation:

For this exercise you can convert the mixed number to an improper fraction:

1. Multiply the whole number part by the denominator of the fraction.

2. Add the product obtained and the numerator of the fraction (This will be the new numerator).

3. The denominator does not change.

Then:

$23\frac{1}{3}= \frac{(23*3)+1}{3}= \frac{70}{3}\ minutes$

You know that he had 30 minutes in time-out, he counted spots on the ceiling for $\frac{70}{3}$ minutes and the rest of the time he made faces at his stuffed tiger.